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Is the area the inside or the outside?
The area is the inside. The perimiter is around. If its a rectangle, to find the area you multiply the lengths of two sides
A rectangle has perimiter 84 ft you also know that the length of the rectangle is six times of the width find the area of this rectangle?
L + W = P/2 = 42 ft. 1/7th of 42 is 6 so L = 36 and W = 6 making the area 216 sqft.
When the perimiter of the rectangle is 38 inches If the rectangle is less than 4 times the width find the area of the rectangle Confused how to do this?
I assume you mean that the length is less than four times the width. Here is the outline. First assume, for simplicity, that the length is EQUAL to 4 times the width. Write two equatios for that - one for the perimeter, one for the area. Solve it, and find the corresponding area. That's basically the minimum area. At the other extreme, make the length equal to the width, and solve again. That would be the maximum area.
How do you find the area and perimiter of a triangle?
To find the area of a triangle find the base and the height of the triangle. Then multiply the base by the height, then divide by 2. To find the perimiter of a triangle add together the outside edge of the triangle. To find the area of a triangle find the base and the height of the triangle. Then multiply the base by the height, then divide by 2. To find the perimiter of a triangle add together the outside edge of the triangle.
How would you find the area of a rectangle if the rectangle was 20cm -9cm?
29
Is the area the inside or the outside?
The area is the inside. The perimiter is around. If its a rectangle, to find the area you multiply the lengths of two sides
Is area inside the square or outside the square?
The area is the inside. The perimiter is around. If its a rectangle, to find the area you multiply the lengths of two sides
How do you find perimiter of a rectangle?
Add together the 4 sides
What is the formula to find perimeter of a rectangle?
to find the perimiter you just add up all the sides....Perimiter is the same for every figure.
When would a architect use the pythagorean theorem?
simply to find area,distance, and perimiter
A rectangle has perimiter 84 ft you also know that the length of the rectangle is six times of the width find the area of this rectangle?
L + W = P/2 = 42 ft. 1/7th of 42 is 6 so L = 36 and W = 6 making the area 216 sqft.
How do you find the area of a rectangular base?
In order to find the area of a rectangle, multiply the length by the width of the rectangle. For example: If the length of a rectangle is 5cm and the width of a rectangle is 2cm, then the area of the rectangle would be 5cm X 2cm = 10cm².
When the perimiter of the rectangle is 38 inches If the rectangle is less than 4 times the width find the area of the rectangle Confused how to do this?
I assume you mean that the length is less than four times the width. Here is the outline. First assume, for simplicity, that the length is EQUAL to 4 times the width. Write two equatios for that - one for the perimeter, one for the area. Solve it, and find the corresponding area. That's basically the minimum area. At the other extreme, make the length equal to the width, and solve again. That would be the maximum area.
How do you find the area and perimiter of a triangle?
To find the area of a triangle find the base and the height of the triangle. Then multiply the base by the height, then divide by 2. To find the perimiter of a triangle add together the outside edge of the triangle. To find the area of a triangle find the base and the height of the triangle. Then multiply the base by the height, then divide by 2. To find the perimiter of a triangle add together the outside edge of the triangle.
When would you need to find the area of a rectangle everyday?
Never
How would you find the area of a rectangle if the rectangle was 20cm -9cm?
29
The length of a rectangle is twice its width If the perimeter of the rectangle is 30yd find its area?
length=2x width=x perimiter=2x+2x+x+x=30= 6x=30 divide by 6, x=5 area=length times width= 2(5)times 5 = 10 times 5= 50yd
