To solve, rewrite the sentence as an equation. "Translate" it into algebra. "is" is rewritten with "=", "25 percent" is rewritten as "25/100" or "1/4", and "what" is rewritten as x. 125 = 1/4 X Once it is written as an equation, solving is simple. Multiply each side by 4. 600 = x.
The equation that represents "a number x decreased by 25 is 100" can be written as ( x - 25 = 100 ). To solve for ( x ), you would add 25 to both sides, resulting in ( x = 125 ).
65% of 125= 65% * 125= 0.65 * 125= 81.25
To find the number, you can set up the equation 0.125x = 35, where x represents the unknown number. To solve for x, you would divide both sides by 0.125, giving you x = 35 / 0.125. Calculating this, you get x = 280. Therefore, 12.5 percent of 280 is 35.
125 is 25% of 500
No, because it is not an equation (or inequality), but simply two expressions separated by a space.
In algebra, you cannot solve 5x25 since there is no equation nor an inequality, only an expression.
To solve, rewrite the sentence as an equation. "Translate" it into algebra. "is" is rewritten with "=", "25 percent" is rewritten as "25/100" or "1/4", and "what" is rewritten as x. 125 = 1/4 X Once it is written as an equation, solving is simple. Multiply each side by 4. 600 = x.
The equation that represents "a number x decreased by 25 is 100" can be written as ( x - 25 = 100 ). To solve for ( x ), you would add 25 to both sides, resulting in ( x = 125 ).
Divide the other side of the equation by 15 and then get the cube root of it. For example if 15X^3 = 1875 then X^3 = 1875 / 15 = 125 th cube root of 125 = 5
65% of 125= 65% * 125= 0.65 * 125= 81.25
To find the number, you can set up the equation 0.125x = 35, where x represents the unknown number. To solve for x, you would divide both sides by 0.125, giving you x = 35 / 0.125. Calculating this, you get x = 280. Therefore, 12.5 percent of 280 is 35.
To find what x5 equals 125, you can set up the equation 5x = 125. To solve for x, divide both sides by 5: x = 125 / 5 = 25. Therefore, x5 equals 125 when x is equal to 25.
125 is 25% of 500
It is: 8 times 125 = 1000
67 adult ticket 58 student tickets total cost $413 total tickets 125 just set up a set of simultaneous equations such as if number of adult tickets is x and number of student tickets is y x+y=125 since 125 tickets are being bought then multiply amount of tickets by ticket cost 4x+2.5y=413 both equations are true so the easiest way to solve it is by solving the first equation first by saying x=125-y plug this new value of x into the second equation by replacing x 4(125-y) +2.5y=413 solve this equation for y then plug the value of y back into x=125-y to find the value for x
Yes I can. I would divide the numerator and the denominator of that fraction each by 125 .