0
No, because it is not an equation (or inequality), but simply two expressions separated by a space.
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What 2 digit number is 1 more than a square and 1 less than a cube?
n = x2 + 1 n = y3 - 1 x2 + 1 = y3 - 1 x2 = y3 - 2 x = (y3 - 2).5 This means that you need to find all cubes where subtracting 2 yields a square: Cubes: 1, 8, 27, 64, 125,... (-2): -1, 6, 25, 62, 123,... (27,25) works. n = 26
How do you simplify 10xy3 times 8x5y3?
10xy3 * 8x5y3 = (10*8)*(x*x5)*(y3*y3) = 80x6y6
How do you solve 5x25?
In algebra, you cannot solve 5x25 since there is no equation nor an inequality, only an expression.
What is Y3( and times-1)?
4
Can you solve for a b and c in the quadratic equation with only a list of data points?
Yes. You need at least three points with x and y coordinates for this. Let the points be: A(x1, y1), B(x2, y2) and C(x3, y3). For each of the points yi = ax2i + bxi + c, so you have to solve a set of simultaneous equations for i=1 ... 3(the y's and x's are no longer variables! the a, b, c are!): y1 = ax21 + bx1 + c, y2 = ax22 + bx2 + c, y3 = ax23 + bx3 + c
How to solve Y3 - 7500y - 125000 equals 0?
Lets start by putting the known number on the other side. Y3 -7500y=125000. There is your start. Take it from here.
How do you solve 16y exponent 3 20y exponent 4?
16y3 / 20y4 = 16/20 * y3/y4 = 4/5 * y3-4 = 4/5 * y-1 or 4/5y
What is 6y-y3?
6y-y3 = 3
What is x3-y3-8?
You would need to know the value of either x or y, so that you could solve for the one independent variable.
How can you solve in substitution methos 4x-y3 and 9x-2y9?
In the absence of any equality signs and proper grammar with great difficulty if not impossible.
How to factirise this x3 y3 equation?
x3-y3
What is the coefficient of -y3 plus 7y3?
-y3 + 7y3
What 2 digit number is 1 more than a square and 1 less than a cube?
n = x2 + 1 n = y3 - 1 x2 + 1 = y3 - 1 x2 = y3 - 2 x = (y3 - 2).5 This means that you need to find all cubes where subtracting 2 yields a square: Cubes: 1, 8, 27, 64, 125,... (-2): -1, 6, 25, 62, 123,... (27,25) works. n = 26
How do you solve y to the 3 plus 9y plus 10y-5 divided by y plus 2?
y3 + 9y + 10y - 5/y + 2 can not be solved, as it is not an equation. If you would like to simplify it, you can reduce it a bit: = y3+ 19y - 5/y + 2
What is y x y x y?
y^3
What is 27-y3 factored completely?
27-y3 factored completely = 24
Iy y equals 3 then y3 y3-y equals?
72
