Y = -2X + 6
The line has a slope of -2 and passes through the point Y=6 on the Y-axis.
-- From the point Y=6 on the Y-axis, move 1 to the right and 2 down. This brings you to the point (1, 4). Mark the point.
-- Place your ruler so that the point Y=6 and the point (1, 4) are both along the ruler's edge, and draw the line.
No, y=8 is a fixed value. A linear equation would look something like y=x+8 - That would produce a straight line graph if the values of x & y were plotted against each other on a graph.
The question contains an expression, not an equation. An expression does not have a graph. Furthermore, even if it were an equation, its form suggests that it would be a linear equation and a linear equation does not open in any direction.
Well I cant graph it for you but its a linear line some points would be (0,-1) (1,-2) (2,-3)(3,-4) (-1,0) (-2,1) (-3,2) and so on
The equation 0 equals 0 is an identity and contributes absolutely nothing to the part of the graph that you should shade or not. The tautological statement can be ignored.
To determine the trend of linear function graph or equation you would simply look at the slope of the line. This is represented by the m in the equation, f(x) = mx + b.
That would be a linear equation.
No, y=8 is a fixed value. A linear equation would look something like y=x+8 - That would produce a straight line graph if the values of x & y were plotted against each other on a graph.
Since y=14x is a perfect linear relation, the correlation would be 1.
The question contains an expression, not an equation. An expression does not have a graph. Furthermore, even if it were an equation, its form suggests that it would be a linear equation and a linear equation does not open in any direction.
If you mean y = 2^x, then no, it is not a linear equation. This is an exponential equation. The graph of this exponential equation would start out near zero on the left-hand side (there is a horizontal asymptote at y = 0) and would gradually increase as you move to the right: overall, it has a curved shaped. If you mean y = 2x, then yes, it is a linear equation.
You would draw a straight horizontal line through the 5 on the y axis.
A linear equation describes a line like 2x+1=y. If you were to graph that equation, then it would give you a line. A quadratic equation is like x^2+2x+1=y. Graphing this equation would give you a U shaped graph called a parabola.
Well I cant graph it for you but its a linear line some points would be (0,-1) (1,-2) (2,-3)(3,-4) (-1,0) (-2,1) (-3,2) and so on
The equation 0 equals 0 is an identity and contributes absolutely nothing to the part of the graph that you should shade or not. The tautological statement can be ignored.
No, this is not a function. The graph would have a vertical line at x=-14. Since there are more than one y value for every given x value, the equation does not represent a function. The slope of the equation also does not exist.
Move 3 over the right side of the equation so the equation would be x = -3. The graph of this would be a verticle line at x= -3
To determine the trend of linear function graph or equation you would simply look at the slope of the line. This is represented by the m in the equation, f(x) = mx + b.