Y = -2X + 6
The line has a slope of -2 and passes through the point Y=6 on the Y-axis.
-- From the point Y=6 on the Y-axis, move 1 to the right and 2 down. This brings you to the point (1, 4). Mark the point.
-- Place your ruler so that the point Y=6 and the point (1, 4) are both along the ruler's edge, and draw the line.
The question contains an expression, not an equation. An expression does not have a graph. Furthermore, even if it were an equation, its form suggests that it would be a linear equation and a linear equation does not open in any direction.
No, y=8 is a fixed value. A linear equation would look something like y=x+8 - That would produce a straight line graph if the values of x & y were plotted against each other on a graph.
y = x^(2) + 4 If you plot it on a graph paper, you will find it produces a curved linea. Hence NOT linear.
Well I cant graph it for you but its a linear line some points would be (0,-1) (1,-2) (2,-3)(3,-4) (-1,0) (-2,1) (-3,2) and so on
The equation 0 equals 0 is an identity and contributes absolutely nothing to the part of the graph that you should shade or not. The tautological statement can be ignored.
That would be a linear equation.
Since y=14x is a perfect linear relation, the correlation would be 1.
The question contains an expression, not an equation. An expression does not have a graph. Furthermore, even if it were an equation, its form suggests that it would be a linear equation and a linear equation does not open in any direction.
If you mean y = 2^x, then no, it is not a linear equation. This is an exponential equation. The graph of this exponential equation would start out near zero on the left-hand side (there is a horizontal asymptote at y = 0) and would gradually increase as you move to the right: overall, it has a curved shaped. If you mean y = 2x, then yes, it is a linear equation.
You would draw a straight horizontal line through the 5 on the y axis.
No, y=8 is a fixed value. A linear equation would look something like y=x+8 - That would produce a straight line graph if the values of x & y were plotted against each other on a graph.
A linear equation describes a line like 2x+1=y. If you were to graph that equation, then it would give you a line. A quadratic equation is like x^2+2x+1=y. Graphing this equation would give you a U shaped graph called a parabola.
Well I cant graph it for you but its a linear line some points would be (0,-1) (1,-2) (2,-3)(3,-4) (-1,0) (-2,1) (-3,2) and so on
No, this is not a function. The graph would have a vertical line at x=-14. Since there are more than one y value for every given x value, the equation does not represent a function. The slope of the equation also does not exist.
The equation 0 equals 0 is an identity and contributes absolutely nothing to the part of the graph that you should shade or not. The tautological statement can be ignored.
Move 3 over the right side of the equation so the equation would be x = -3. The graph of this would be a verticle line at x= -3
To determine the trend of linear function graph or equation you would simply look at the slope of the line. This is represented by the m in the equation, f(x) = mx + b.