2y + 10 = x can be written as y = x/2 - 5. This defines a straight line graph with a slope of 1/2 and a y intercept of -5.
x + 2y = -5 2x + 3x = -9 5x = -9 x + 2y = -5 x = -2y - 5 5(-2y - 5) = -9 -10y - 25 = -9 -10y = 16 y = -5/8 x = -2y - 5 x = -2(-5/8) - 5 x = -5/4 - 5 x = -25/4 (-25/4, -5/8)
2y = x + 4Divide each side by 2:y = (1/2)x + 2The graph is a straight line with a slope of (1/2) and a y-intercept of 2.
-x+2y = 6 2y = x+6 y = 1/2x+3 Therefore the slope is 1/2 and the y intercept is 3
if 2y-x=4, than y=1/2*x+2 we can now see that the graph is linear with slope 1/2 and goes through point (0,2)
When y=4, x=8/5
x = 5 x-2y = 6 => x = 6+2y 6+2y = 5 2y = 5-6 2y = -1 y = -1/2 and x = 5 Point of intersection: (5, -1/2)
2y + 10 = x can be written as y = x/2 - 5. This defines a straight line graph with a slope of 1/2 and a y intercept of -5.
2y = 5x - 10Putting into Slope-Intercept form, we have y = 5/2 x - 5. So, the y-intercept is -5 and the slope is 5/2 or 2.5. (x-intercept is 2).
The equation "x plus 2y equals 5" is: x + 2y = 5 2y = 5 - x y = 5/2 - 1/2x y = -1/2x + 5/2
x + 2y = -5 2x + 3x = -9 5x = -9 x + 2y = -5 x = -2y - 5 5(-2y - 5) = -9 -10y - 25 = -9 -10y = 16 y = -5/8 x = -2y - 5 x = -2(-5/8) - 5 x = -5/4 - 5 x = -25/4 (-25/4, -5/8)
2y = x + 4Divide each side by 2:y = (1/2)x + 2The graph is a straight line with a slope of (1/2) and a y-intercept of 2.
Add the two equations together. The x disappears. 2y - x = 3 + x = 3y - 5 ------------------------ 2y = 3y -2 Can you finish it from there?
x = y+3 x+2y = 9 => x = 9-2y y+3 = 9-2y 2y+y = 9-3 3y = 6 y = 2 and x = 5
-x+2y = 6 2y = x+6 y = 1/2x+3 Therefore the slope is 1/2 and the y intercept is 3
if 2y-x=4, than y=1/2*x+2 we can now see that the graph is linear with slope 1/2 and goes through point (0,2)
2x-3y=5 and x-2y=12x-3y+2y=5 and x-2y+2y=12x-y=5 and x=12(1)-y=52-y=52-y-2=5-2-y=3y=-3(x,y) is (1,-3)