How you take a number that is divided by 3 and gives you a remainder of 1.Then you add that number that you have divide by 3 that gives you a remainder of 2. the remainder of the sum when you divide?

Answer 1

Let the first number be represented as ( n ), which can be expressed in the form ( n = 3k + 1 ) for some integer ( k ). The second number, which gives a remainder of 2 when divided by 3, can be represented as ( m = 3j + 2 ) for some integer ( j ). When you add these two numbers, ( n + m = (3k + 1) + (3j + 2) = 3(k + j) + 3 ), which simplifies to ( 3(k + j + 1) ). Therefore, the sum ( n + m ) is divisible by 3, resulting in a remainder of 0 when divided by 3.