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Is it true or false the solution set of an equation of a circle is all of the points that lie on the circle?
True. The solution set of an equation of a circle consists of all the points that lie on the circle itself. This set is defined by the equation ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. Thus, any point that satisfies this equation lies on the circle.
The solution set of an equation of a circle is all of the points that lie on the circle.?
Yes, the solution set of an equation of a circle consists of all the points that satisfy the equation, representing the circle's boundary. Typically, this equation is in the form ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. Each point ((x, y)) that meets this condition lies exactly on the circle.
The solution set of an equation of a circle is all of the points that lie on a cirlce?
Yes, the solution set of an equation of a circle consists of all the points that satisfy the equation, which typically takes the form ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is its radius. Any point ((x, y)) that lies on the circle will fulfill this equation, thus forming the complete solution set.
How can you tell if a point is a solution to the equation?
Substitute the coordinates of the point into the equation and if the result is a true statement then the point is a solution, and if not it isn't.
How do you solve x squared plus y squared equals 13?
The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.
Is each point that lies on a circle satisfies the equation of the circle true or false?
True
Is it true or false the solution set of an equation of a circle is all of the points that lie on the circle?
True. The solution set of an equation of a circle consists of all the points that lie on the circle itself. This set is defined by the equation ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. Thus, any point that satisfies this equation lies on the circle.
How can you determine whether a point is a solution to system of equations?
You substitute the coordinates of the point in the equation. If the result is true then the point is a solution and if it is false it is not a solution.
The solution set of an equation of a circle is all of the points that lie on the circle.?
Yes, the solution set of an equation of a circle consists of all the points that satisfy the equation, representing the circle's boundary. Typically, this equation is in the form ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. Each point ((x, y)) that meets this condition lies exactly on the circle.
The solution set of an equation of a circle is all of the points that lie on a cirlce?
Yes, the solution set of an equation of a circle consists of all the points that satisfy the equation, which typically takes the form ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is its radius. Any point ((x, y)) that lies on the circle will fulfill this equation, thus forming the complete solution set.
How can you tell if a point is a solution to the equation?
Substitute the coordinates of the point into the equation and if the result is a true statement then the point is a solution, and if not it isn't.
Is the distance from the point of concurrency of the angle bisectors of a triangle to a point on the inscribed circle is the radius of the circle True or False?
false
In the standard equation of a circle centered at any point a change in value of the number that is part of the x-term results in a vertical movement?
false
What does solving the equation for a line tell us?
A line is represented by an equation. Each solution of the equation is a point on the line, and each point on the line is a solution to the equation. So the line is just the graph of the solution set of the equation.
How do you solve x squared plus y squared equals 13?
The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.
Is the point 69 a solution of the equation y12x 6?
If this question is asking: is the point (6,9) a solution of the equation y = 12x + 6, then NO, it's not a solution.
How do you know if a point is a solution if you are looking at the graph?
To determine if a point is a solution on a graph, check if the point's coordinates (x, y) satisfy the equation of the graph. If the point lies on the curve or line representing the equation, it is a solution. For instance, if the equation is y = f(x), substitute the x-coordinate into the equation to see if it equals the y-coordinate. If it does, the point is a solution.
