It is a progression by threes: 12=0,15=1, so 18=2,21=3,24=4 and 27=5.
27-12=15 -x-=+ 15/5=3 12- -3= +15 12+15=27 n= -3
12
3n = 15 + 12 = 27, 27/3 = 9 = n
122 !
hcf(10, 21) = 1 ⇒ 10 & 21 relatively prime hcf(12, 54) = 6 ⇒ 12 & 54 not relatively prime hcf(15, 27) = 3 ⇒ 15 & 27 not relatively prime hcf(21, 38) = 1 ⇒ 21 & 38 relatively prime
27-12=15 -x-=+ 15/5=3 12- -3= +15 12+15=27 n= -3
12
3n = 15 + 12 = 27, 27/3 = 9 = n
15
122 !
6x - 12 = 3x + 15 3x = 27 x = 9
27-g = 2g+12 -3g = -15 g = 5
hcf(10, 21) = 1 ⇒ 10 & 21 relatively prime hcf(12, 54) = 6 ⇒ 12 & 54 not relatively prime hcf(15, 27) = 3 ⇒ 15 & 27 not relatively prime hcf(21, 38) = 1 ⇒ 21 & 38 relatively prime
2 3rds = 4/6 = 6/9 = 8/12 = 10/15 = 12/18 = 14/21 = 16/24 = 18/27 = 20/30
To solve for b in the equation b + 15 = 27, you need to isolate b on one side of the equation. To do this, you can subtract 15 from both sides of the equation. This gives you b = 27 - 15, which simplifies to b = 12. Therefore, b equals 12 in the given equation.
10 and 21
3 is a multiple of 15, 21, and 27.