The question starts with "If 1 is 3 ..."
That statement is clearly false and so, by Boolean algebra, any clause can follow.
So "6 is 5", "6 is 6", "6 is a banana" are all valid.
Here is the number line . ....-2, -7/4. -3/2 , -5/4, -1 , -3/4 , -1/2, -1/4, 0, 1/4, 1/2, 3/4, 1 , 5/4 , 3/2, 7/4, 2 ....
1.3333
1 * (1-4) = 1*(-3) = -3
1 goes into 3 and 4.
1 4/3
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Here is the number line . ....-2, -7/4. -3/2 , -5/4, -1 , -3/4 , -1/2, -1/4, 0, 1/4, 1/2, 3/4, 1 , 5/4 , 3/2, 7/4, 2 ....
The only number that goes into both 3 and 4 is 1.
you minus 1 =4-1 =3
The midway point of 1/4 and 3/4 is 1/2 * (1/4 + 3/4) = 1/2 * (4/4) = 1/2
1.3333
4/3 = 1 and 1/3 as a mixed number
3*1*3/4 = 9/4 or 2 and 1/4
1 3/4, that's a 1 (whole number) and 3/4 (fraction 3 over 4)
1 * (1-4) = 1*(-3) = -3
(4^3)-(3^3)-(9+1)
1 4/3