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What is the ratio of the length of a side to the perimiter of a regular pentagon?
In a regular pentagon, all sides are of equal length. If we denote the length of one side as ( s ), the perimeter ( P ) of the pentagon is ( 5s ). Therefore, the ratio of the length of a side to the perimeter is ( \frac{s}{5s} = \frac{1}{5} ). Thus, the ratio is ( 1:5 ).
How do you calculate the volume of a pentagonal pyramid?
V = (1/3) (area of the base) (height) Area of a pentagon = 1/2 x apothem length x 5 x length of a side of the pentagonthe apothem is the perpendicular distance from the center of the pentagon to the side of the pentagon
What is the area of a regular pentagon with a side length of ten units?
A regular pentagon has five (5) equilateral triangles within it. Find the area of each triangle (1/2bh where b is the base of the triangle or the length of a side of the pentagon, and h is the height of the triangle or the apothem of the pentagon) and multiply the area of the triangle times five (5).
If a rectangular pentagon has a ide of length 2x 1 what is the perimeter of the pentagon?
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What is the area of a regular pentagon with a side length of 9 millimeters an an apothem length of 6.2 millimeters?
The formula for finding the area of a regular pentagon is: A= 1/4*{sqrt[5(5+2sqrt(5)]}*a^2 where * means multiply, ^2 means 't the power of 2 or squared) You only need the length of the side. So the area of this pentagon is given by A= 1/4{sqrt[5(5+2sqrt(5)]}*.9^2 =1/4*(6.8819)*0.81 = 1.3936 sq mm.
What is the ratio of the length of a side to the perimiter of a regular pentagon?
In a regular pentagon, all sides are of equal length. If we denote the length of one side as ( s ), the perimeter ( P ) of the pentagon is ( 5s ). Therefore, the ratio of the length of a side to the perimeter is ( \frac{s}{5s} = \frac{1}{5} ). Thus, the ratio is ( 1:5 ).
How do you calculate the volume of a pentagonal pyramid?
V = (1/3) (area of the base) (height) Area of a pentagon = 1/2 x apothem length x 5 x length of a side of the pentagonthe apothem is the perpendicular distance from the center of the pentagon to the side of the pentagon
What is the area of a regular pentagon with a side length of ten units?
A regular pentagon has five (5) equilateral triangles within it. Find the area of each triangle (1/2bh where b is the base of the triangle or the length of a side of the pentagon, and h is the height of the triangle or the apothem of the pentagon) and multiply the area of the triangle times five (5).
If a rectangular pentagon has a ide of length 2x 1 what is the perimeter of the pentagon?
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What is the formula for finding area of a pentagon?
[ONLY WORKS FOR REGULAR PENTAGONS] I don't the exact formula, BUT, from what I learned in Geometry last year, I remember that if you have the radius from the center perpendicular to a side [for height] and if you have the length of the side of the pentagon, you can use a simple 1/2 times base time height to get 1/5th of the area. Then you just take that and multiply it by 5 to get the area of the whole pentagon. I know it looks complicated, but it's pretty simple: I have a REGULAR pentagon that I chop into 5 triangles I have the height = 2 I have the base [or the length of 1 side of the pentagon]= 4 1/2xbasexheight= 1/2x2x4= 4 So now you have the area of 1 triangle and multiply by 5 4x5= 20 your pentagon is 20 units squared. I hope this helped.
The perimeter of a square with the length of 15 feet is equal to the perimeter of a regular pentagon What is the length of one side of the pentagon in yards?
A regular pentagon has a perimeter of 5s. We set this equal to 15, and solve for s, and convert to yards.5s = 15s = 33 feet converted to yards is 3/3 = 1 yard.
What is the area of a regular pentagon with a side length of 9 millimeters an an apothem length of 6.2 millimeters?
The formula for finding the area of a regular pentagon is: A= 1/4*{sqrt[5(5+2sqrt(5)]}*a^2 where * means multiply, ^2 means 't the power of 2 or squared) You only need the length of the side. So the area of this pentagon is given by A= 1/4{sqrt[5(5+2sqrt(5)]}*.9^2 =1/4*(6.8819)*0.81 = 1.3936 sq mm.
How do find the volume of a pentagon?
If you mean a pentagonal prism, then find the area of the pentagon 1st. Length of 1 side x 1.7, then multiply by the height of the prism. But I dont really know the regular Pentagon volume. sorry... hope you dont hate me for that.
In a regular pentagon whose area is 140 sq. in. and side is 8 in. the apothem length is?
To find the apothem length ( a ) of a regular pentagon, you can use the formula for the area ( A ) of a pentagon: [ A = \frac{1}{2} \times Perimeter \times Apothem ] The perimeter ( P ) of the pentagon is ( 5 \times \text{side} = 5 \times 8 = 40 ) in. Given the area ( A = 140 ) sq. in., we can rearrange the formula to find the apothem: [ 140 = \frac{1}{2} \times 40 \times a \implies 140 = 20a \implies a = \frac{140}{20} = 7 \text{ in.} ] Thus, the apothem length is 7 inches.
What is the area of a regular pentagon with a side length of 9.4 feet and an apothem length of 6.5 feet?
The area ( A ) of a regular pentagon can be calculated using the formula ( A = \frac{1}{2} \times \text{perimeter} \times \text{apothem} ). The perimeter of the pentagon is ( 5 \times 9.4 = 47 ) feet. Thus, the area is ( A = \frac{1}{2} \times 47 \times 6.5 = 152.75 ) square feet.
What is the ratio of the length of an equilateral pentagon to its perimeter?
A regular pentagon has all sides the same length. A pentagon has 5 sides. Its perimeter is the sum of its side_lengths which is 5 x side_length → ratio side_length : perimeter = 1 x side_length : 5 x side_length = 1 : 5
What is the area of a regular pentagon if the radius r of the circumcircle is 3.4 cm and half the side length a is 2 cm rounded to 1 decimal place?
In a regular pentagon there are 5 vertices which connect to the circumcentre each a distance r = 3.4 cm away. This creates 5 triangles inside the pentagon; so the area of the pentagon is the sum of these five triangles; as the pentagon is regular, this is the same as 5 times the area of one of these triangles. The length of each side of the pentagon is twice half the length of one side → side = 2 × a = 2 × 2 cm Consider one side and the two radii connecting its ends to the circumcentre; this is an isosceles triangle, so dropping a perpendicular from the circumcentre to the side of the pentagon bisects the base of the triangle (side of the pentagon). From this the height of the triangle can be calculated using Pythagoras: half_side² + height² = radius² → (a cm)² + height² = (r cm)² →(2 cm)² + height² = (3.4 cm)² → height² = (3.4 cm)² - (2 cm)² → height = √(3.4² - 2²) cm area_pentagon = 5 × area_triangle = 5 × ½ × base × height = 5 × ½ × (2 × 2 cm) × √(3.4² - 2²) cm = 10 × √7.56 cm² = 27.495... cm² ≈ 27.5 cm² to 1 dp
