23 divided by 135 is 0.17037
3 is the remainder when 23 is divided by 10. 2 x 10 = 20, and 23 is 3 more than 20.
112
20
-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10
23 divided by 135 is 0.17037
20 20 - 1978 2009-10-23 was released on: USA: 23 October 2009
range = biggest number - smallest number in this case range = 135 - 8 = 127
3 is the remainder when 23 is divided by 10. 2 x 10 = 20, and 23 is 3 more than 20.
112
20
-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10-53/4- 67/20= -23/4 - 127/20 = -115/20 - 127/20 = -242/20 = =121/10 = -121/10
To calculate the number of atoms, we need to use Avogadro's number and the molecular weight of zinc. The molar mass of zinc is 65.38 g/mol. First, convert grams to moles: 135 g / 65.38 g/mol = 2.06 moles. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms: 2.06 moles * 6.022 x 10^23 atoms/mol = 1.24 x 10^24 atoms of zinc.
There are 17.037037... (repeating) lots of 135 cm in 23 metres.
10 18 15 23 20
45*2 = 90 so 45*20 = 900 45*3 = 135 So 45*23 = 45*20 + 45*3 = 900 + 135 = 1035
20 moles x 6.02x10^23 atoms/mole = 1.2x10^25 atoms