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If the relationship is reflexive then the answer is yes, and if not, it is no.
3x-5=3x+5 There is no solution.
4x + 5 = 3x + 84x-3x + 5 - 5 = 3x - 3x + 8 -5x = 3
the sum of -5 and 3x
3x - 5 + 3x = 1x + 15 3x + 3x -1x = 15 + 5 5x = 20 5x/5 = 20/5 x = 4
(3x - 5)5= (3x + -5)5= (5C0)(3x)5(-50)+(5C1)(3x)4(-5)1+(5C2)(3x)3(-5)2+(5C3)(3x)2(-5)3+(5C4)(3x)1(-5)4+(5C5)(3x)0(-5)5= (1)(243x5)(1)+(5)(81x4)(-5)+(10)(27x3)(25)+(10)(9x2)(-125)+(5)(3x)(625)+(1)(1)(-3125)= 243x5 - 2,025x4 + 6,750x3 - 11,250x2 + 9,375x - 3125
3x^5 If these are 5 of 3x multiplied together the it must be (3x)^5 =3^5 times x^5
3x-5=3x+5 There is no solution.
8
3x+5 Solution- 3x+5=0 3x= (-5) x= (-5)/3
4x + 5 = 3x + 84x-3x + 5 - 5 = 3x - 3x + 8 -5x = 3
the sum of -5 and 3x
3x - 5 + 3x = 1x + 15 3x + 3x -1x = 15 + 5 5x = 20 5x/5 = 20/5 x = 4
-2
(3x - 5)5= (3x + -5)5= (5C0)(3x)5(-50)+(5C1)(3x)4(-5)1+(5C2)(3x)3(-5)2+(5C3)(3x)2(-5)3+(5C4)(3x)1(-5)4+(5C5)(3x)0(-5)5= (1)(243x5)(1)+(5)(81x4)(-5)+(10)(27x3)(25)+(10)(9x2)(-125)+(5)(3x)(625)+(1)(1)(-3125)= 243x5 - 2,025x4 + 6,750x3 - 11,250x2 + 9,375x - 3125
3x + 5 = 20 Subtract '5' from both sides 3x = 15 Divide both sides by '3' x = 5 The answer!!!!!
5=3x+2 3x+2-2=5-2 3x=3 ------ 3 x=1
3x+5=2, 3x=2-5 (sign changes) 3x=-3 x=-1