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If 48 square inches are subtracted from the area of a square table the result would be equal to twice the perimeter what is the length of the side of the table?
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The peremiter of a rectangle is 234 in the length exceeds the width by 39 inches find the length and width?
Since the length exceeds the width by 39 inches, if x is the width, then you can express the length as x + 39. Now, use the formula for the perimeter of a rectangle, replacing known values: perimeter = 2(length + width) 234 = 2(x + 39 + x) Solving this for "x" will result in the width; add 39 to get the length.
What is the area of a square with a perimeter of 12 feet?
The perimeter of a square is four times the length of any of its sides. Thus, you can divide the perimeter by 4, and then square the result to get the area.
In perimeter do you use inches or centimeters?
You can use either. Of course, using the standard system (centimeters) is preferable. If measurements are given in inches, by adding the sides, the final result will also be in inches. If sides are given in anstroms, perimeter will also be in angstroms. Etc.You can use either. Of course, using the standard system (centimeters) is preferable. If measurements are given in inches, by adding the sides, the final result will also be in inches. If sides are given in anstroms, perimeter will also be in angstroms. Etc.You can use either. Of course, using the standard system (centimeters) is preferable. If measurements are given in inches, by adding the sides, the final result will also be in inches. If sides are given in anstroms, perimeter will also be in angstroms. Etc.You can use either. Of course, using the standard system (centimeters) is preferable. If measurements are given in inches, by adding the sides, the final result will also be in inches. If sides are given in anstroms, perimeter will also be in angstroms. Etc.
What is the width of the rectangle if the length is 7.5 centimeters and the perimeter is 38?
Perimeter = 2(Length + Width)38 = 2*(7.5 + W)38 = 15 + 2W so 2W = 23 so that W = 11.5 cmA peculiar result since normally the length is larger than the width.
How do you find the area of a square with the perimeter?
A square has all 4 of its perimeter lengths equal. Thus the length of the perimeter divided by 4 will give you the 'unitary' dimension. Multiply this 'unitary' dimension by itself (square it) and the result is the area of the square in question.
The peremiter of a rectangle is 234 in the length exceeds the width by 39 inches find the length and width?
Since the length exceeds the width by 39 inches, if x is the width, then you can express the length as x + 39. Now, use the formula for the perimeter of a rectangle, replacing known values: perimeter = 2(length + width) 234 = 2(x + 39 + x) Solving this for "x" will result in the width; add 39 to get the length.
If you know the perimeter how do you find length?
To find the length given the perimeter of a rectangle, you would need the width as well. Since the perimeter of a rectangle is the sum of all its sides (2 lengths + 2 widths), you can rearrange the formula to solve for the length by subtracting twice the width from the perimeter and dividing the result by 2. Formula: Length = (Perimeter - 2*width) / 2.
If you know a perimeter of a square but not the length or width how do you find the area?
Divide the perimeter by 4 and then square the result to find the area of the square.
If forty eight square inches are subtracted from the area of a square table the result would be equal to twice the perimeter What is the length of the side of the table?
p = 4s a = s2 2p = a - 48 8s = a - 48 8s = s2 - 48 -s2 + 8s + 48 = 0 s2 - 8s - 48 = 0 (s - 12)(s - 4) = 0 s = 12 or 4
What is the area of a square with a perimeter of 12 feet?
The perimeter of a square is four times the length of any of its sides. Thus, you can divide the perimeter by 4, and then square the result to get the area.
In perimeter do you use inches or centimeters?
You can use either. Of course, using the standard system (centimeters) is preferable. If measurements are given in inches, by adding the sides, the final result will also be in inches. If sides are given in anstroms, perimeter will also be in angstroms. Etc.You can use either. Of course, using the standard system (centimeters) is preferable. If measurements are given in inches, by adding the sides, the final result will also be in inches. If sides are given in anstroms, perimeter will also be in angstroms. Etc.You can use either. Of course, using the standard system (centimeters) is preferable. If measurements are given in inches, by adding the sides, the final result will also be in inches. If sides are given in anstroms, perimeter will also be in angstroms. Etc.You can use either. Of course, using the standard system (centimeters) is preferable. If measurements are given in inches, by adding the sides, the final result will also be in inches. If sides are given in anstroms, perimeter will also be in angstroms. Etc.
How is the perimeter and area of a square related?
There is no direct relationship. The perimeter is proportional to the length of the side (if you increase the side by a factor of 10, the perimeter will also increase by a factor of 10); the area is proportional to the square of the side length (if you increase the length of a side by a factor of 10, the area will increase by a factor of 100).If you know the perimeter, divide it by 4 and then square the result, to get the area (A = (P/4)2); if you know the area, take the square root and then multiply by 4 to get the perimeter (P = root(A) x 4).There is no direct relationship. The perimeter is proportional to the length of the side (if you increase the side by a factor of 10, the perimeter will also increase by a factor of 10); the area is proportional to the square of the side length (if you increase the length of a side by a factor of 10, the area will increase by a factor of 100).If you know the perimeter, divide it by 4 and then square the result, to get the area (A = (P/4)2); if you know the area, take the square root and then multiply by 4 to get the perimeter (P = root(A) x 4).There is no direct relationship. The perimeter is proportional to the length of the side (if you increase the side by a factor of 10, the perimeter will also increase by a factor of 10); the area is proportional to the square of the side length (if you increase the length of a side by a factor of 10, the area will increase by a factor of 100).If you know the perimeter, divide it by 4 and then square the result, to get the area (A = (P/4)2); if you know the area, take the square root and then multiply by 4 to get the perimeter (P = root(A) x 4).There is no direct relationship. The perimeter is proportional to the length of the side (if you increase the side by a factor of 10, the perimeter will also increase by a factor of 10); the area is proportional to the square of the side length (if you increase the length of a side by a factor of 10, the area will increase by a factor of 100).If you know the perimeter, divide it by 4 and then square the result, to get the area (A = (P/4)2); if you know the area, take the square root and then multiply by 4 to get the perimeter (P = root(A) x 4).
If a rectangle has perimeter of 1.57 kilomteres its length is 168 meters what is breadth?
Perimeter = 2*(Length + Breadth) So, 1570 = 2*(168 + Breadth) 785 = 168 + Breadth Breadth = 617 metres Which is rather an unusual result because normally the length is greater than the breadth.
Fing the area of a square if the perimeter of that sqauare is 32 cm?
Divide the perimeter length by 4 ie 8cm and square the result ie 8cm x 8cm = 64sq cm
What is the width of the rectangle if the length is 7.5 centimeters and the perimeter is 38?
Perimeter = 2(Length + Width)38 = 2*(7.5 + W)38 = 15 + 2W so 2W = 23 so that W = 11.5 cmA peculiar result since normally the length is larger than the width.
How do you find the area of a square with the perimeter?
A square has all 4 of its perimeter lengths equal. Thus the length of the perimeter divided by 4 will give you the 'unitary' dimension. Multiply this 'unitary' dimension by itself (square it) and the result is the area of the square in question.
When 20 is subtracted from -4 the result is?
The result is: -4-20 = -24
