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Q: If you know a perimeter of a square but not the length or width how do you find the area?

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Important to note are these formulae: Perimeter_of_rectangle = 2 x (length + width) Area_of_rectangle = length x width So if the perimeter and area are known, then: 2 x (length + width) = perimeter => length + width = perimeter / 2 => length = perimeter / 2 - width length x width = area => (perimeter / 2 - width) x width = area (substituting for length given above) => perimeter / 2 x width - width2 = area => width2 - perimeter / 2 x width + area = 0 which is a quadratic and can be solved either by factorization or by using the formula: width = (perimeter / 2 +/- sqrt(perimeter2 / 4 - 4 x area)) / 2 = (perimeter +/- sqrt(perimeter2 - 16 x area)) / 4 This will provide two values for the width. However, each of these values is the length for the other, so the larger value is the length and the smaller value is the width. Sometimes only 1 value will be found for the width above. In this case, the rectangle is actually a square which means that the length and width are both the same. Examples: 1. perimeter = 6, area = 2 width2 - perimeter / 2 x width + area = 0 => width2 - 6 / 2 x width + 2 = 0 => width2 - 3 x width + 2 = 0 => (width - 2) x (width - 1) = 0 => width = 2 or 1. So the length is 2 and the width is 1. 2. perimeter = 12, area = 9 width2 - perimeter / 2 x width + area = 0 => width2 - 12 / 2 x width + 9 = 0 => width2 - 6 x width + 9 = 0 => (width - 3)2 = 0 => width = 3 So the rectangle is a square with both length and width of 3.

The area is the length times the width. The perimeter is two times the length plus two times the width.

If you are given the width and the perimeter, then figure out what the length is then calculate the area... hope this helps :)

You don't measure the length and width in square feet. Square feet is an area. You measure the length and width in feet, then multiply them to get the area in square feet.

In order to make sense of this question it is necessary to assume that the area is 28 SQUARE metres and not 28 metres as stated. Then, Length = Area/Width = 28/4 = 7m Then perimeter = 2*(Length + width) = 2*(7 + 4) = 2*11 = 22 metres.

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Area = Legth x Width In a square, Length = Width Therefore Area = Length x Length (or Width x Width) Area = Length squared Length = Square Root of 800 Perimeter = 4 x length Perimeter = 4 x Square Root of 800 Perimeter = 113.14

perimeter is the measure around the figure; area is the measure within the figure formula: perimeter: length+length+width+width=perimeter (for square or rectangle) area: length times width= area ( for square or rectangle)

The area of a square is: A = Width × Height or A = Length * Length = Length^2 The Perimeter of a square is: P = Length + Length + Length + Length = 4 * Length

You multiply length times width

The perimeter is found by adding the length of each side. The area is found by multiplying the length of the square by the width.

36, area is equal to length X width, perimeter is equal to 2(length)+2(width) in a square length is equal to width, so we take the square root of the area to find that both are 9, which means the perimeter is 9 X 4, 36.

you times the length by the width to get the area of any rectangular or square shapes

if you have the area. divide the area by the length to get the width. If you have the perimeter subtract the length twice and divide the number you have by two. If it is a square the width is the same as the length.

you need length and width length multiply width = area length + length + width + width = perimeter

Perimeter = 2 lengths + 2 widths 1/2 perimeter = length + width Length = 1/2 perimeter - width Area = length x width That's (1/2 perimeter - width) x (width) .

For a given perimeter, its a square.

If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.

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