The answer to the problem of 4 over 9w equals negative 8 is w equals -18.
-9w + zt + wz - 9t = (z - 9)(t + w)
w = 70.25
w = hf - E
Suppose W/3 is the even integer X. Then the numbers are (X-2, X , X+2)If W/3 is not an even integer then there is no solution.
The answer to the problem of 4 over 9w equals negative 8 is w equals -18.
9w - 3.5 = 1 9w = 4.5 w = 0.5
w = 2
6-9w=24 subtract 6 from both sides -9w=18 now divide -9 to both sides to live w alone w= -2
Area of triangle = 0.5 * width * height So 27 = 0.5 * w * (w-3) or 54 = w2 - 3w ie w2 - 3w - 54 = 0 w2 - 9w + 6w - 54 = 0 w(w - 9) + 6(w - 9) = 0 ie (w - 9)(w + 6) = 0 So w = 9 or w = -6 But since w is a width, it must be positive and so w = 9 cm.
-9w + zt + wz - 9t = (z - 9)(t + w)
-36 + 2w = -8w + w -36 + 2w = -7w -36 = -7w - 2w -36 = -9w w = -36/-9 = 4
If you mean 6-9w = 24 then the value of w works out as -2
Any multiple of 9w
54 degrees. The minor arc is congruent to the opposite angle (54)
w=8
It is: (5w+1)(w-2) when factored