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Q: What is the answer to this algebra 1 problem -36 plus 2w equals -8w plus w?

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x = (P - 2W) / 2

w=4

3w - 2 = 2w + 3 Add 2 to both sides: 3w = 2w + 5 Subtract 2w from both sides: w = 5

5w+2 = 2w+5 5w-2w = 5-2 3w = 3 w = 1

w=10

W/3 + 2W/3 is one possible answer.

what is w if 2w = 16

2L+2W=P (S2w) Subtract 2W from both sides 2L=P-2W (D2) Divide both sides by 2 L=(P-2W)/2

12x-14w+103y+72+16-56+0-65+2w+0 original = 12x-14w+2w+103y+72+16-56+0-65+0 group = 12x-12w+103y-33 answer

120 - 76 = w+w. So: 2w = 44. So: w=22.

2l + 2w = P Subtract 2l from both sides: 2w = P - 2l Divide both sides by 2: w = P/2 - l

There is no indication as to what B represents and consequently no possibility of answering the question.

6 + w - 2w - 11 + 6w = -5 + 5w

Using basic algebra we can solve this problem. First we need to write out the problem:5-32+2w = -7-27+2w = -72w = 20w = 10

It is: 2w which in algebra means 2 times w

2w

-5w + 9

It is 12w.

2w + 16 = - 6w - 8 2w + 16 + 6w = - 8 8w + 16 = - 8 8w = - 8 - 16 8w = - 24 w = - 3

22

w = 3 16 = 4w + 2w - 2 Move the 2 to other side 16 + 2 = 4w + 2w 18 = 6w 18 / 6 = 3 = w

(2w + 3)(w + 5)

Not sure that you can slove anything. -2w = r + s is one linear equation in 3 unknown variables. You need three independent equations in 3 variables to be able to solve them.

It is: 6w-2

a = L x W: area equals length times the width. p = 2L + 2W: perimeter equals 2 times the length plus 2 times the width so L = (p - 2W)/2