12
The support provided by 5 samples would be 5 times greater than that of 1 sample, but the weight expressed by the 500 gram weight remains constant.
2.674 g
0.02
150
Density = mass/volume, so:36 grams/ 12 milliliters3 grams/ milliliter
The density of the sample can be calculated by dividing the mass by the volume. In this case, 55 grams divided by 22 milliliters is approximately 2.5 grams per milliliter.
Both samples contain the same number of carbon atoms because the number of atoms in a sample is determined by Avogadro's number (6.022 x 10^23) and not by the mass of the sample itself.
The density of the seawater sample is calculated by dividing the mass (158 grams) by the volume (156 ml). Therefore, the density of the seawater sample is approximately 1.01 grams per milliliter.
The support provided by 5 samples would be 5 times greater than that of 1 sample, but the weight expressed by the 500 gram weight remains constant.
2.674 grams
a metal sample weigs 56.8 gramsHow many ounces does this sample weigh?
To calculate the amount of pure silver in the sample, multiply the mass of the ore by the percentage of silver: 0.53 grams * 5.4% = 0.02862 grams of silver. To convert grams to milligrams, multiply by 1000: 0.02862 grams * 1000 = 28.62 milligrams of pure silver in the sample.
7
23.3 grams
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0.2188
The mass of the substance is 20 grams in a 10 ml sample. Therefore, the substance has a density of 2 grams/ml. For a 200 ml sample of the same substance, the mass would be 400 grams (200 ml x 2 grams/ml).