The sum of the four angles is 360 degrees. Three of the angles add up to 310 so the fourth must be 360 - 310 = 50 degrees.
If those are the angles of a quadrilateral then the 4th angle is 360-100-80-100 = 80 degrees
80 degree
125 degrees
No because the 4 interior angles of a quadrilateral add up to 360 degrees
A trapazoid has those angles
If those are the angles of a quadrilateral then the 4th angle is 360-100-80-100 = 80 degrees
50 degrees (360 degrees in a quadrilateral)
125°
4
80 degree
It is 100 degrees.
125 degrees
No because the 4 interior angles of a quadrilateral add up to 360 degrees
A trapazoid has those angles
Well, darling, that quadrilateral is a simple convex quadrilateral because all the interior angles add up to 360 degrees. It's also a quadrilateral with no parallel sides or right angles, so it's not a square, rectangle, parallelogram, or rhombus. Just a sassy little quadrilateral with angles of 110, 100, 80, and 70 degrees.
Yes as for example a square has 4 interior equal angles of 90 degrees.
It is a parallelogram or a rhombus