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If Jan is older than Mike and the sum of their ages is 15 and the quotient of their age is four what is Jan's age?
Jan 12 and Mike 3 ..... 12/3 = 4 and 12 + 3 = 15
Let Jan's age be x years and Mike's age be y years. Given that Jan is older than mike and the sum of their ages is 15. That implies x + y = 15. Also given that the quotient of their age is four. We know that Jan is older than mike. So, the quotient of their age is four implies x/y = 4. => x = 4y. We need to find the age of Jan. Substitute the value of x = 4y in the equation x + y = 15. x + y = 15 => 4y + y = 15 => 5y = 15 => y = 15/5 => y = 3. So, the age of Mike is 3 years. Substitute the value of y in the equation x + y = 15. x + 3 = 15 x = 15 - 3 x = 12 Jan is 12 years old.
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