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What is 3 plus 2 times A plus B times 4 divided by 2 minus 4 simplified expression?
3+2*A+B*4/2-4 = 3 + 2A + 2B - 4 = 2A + 2B - 1
3 plus 5 equals 4times b therefore b equals?
3 + 5 = 4*b so 8 = 4*b Divide both sides by 4: 2 = b
Factor a squared plus 4a plus 4 - b squared?
(a + 2 - b) (a + 2 + b)
2(a plus b) plus 3(a plus b) plus 5a?
10a + 5b
What is the value of b when 3 times b plus 4 equals b plus 12?
3b+4 = b+12 3b-b = 12-4 2b = 8 b = 4
What is 3 plus 2 times A plus B times 4 divided by 2 minus 4 simplified expression?
3+2*A+B*4/2-4 = 3 + 2A + 2B - 4 = 2A + 2B - 1
How do you factor b2 - 7b plus 12?
b^2 - 7b + 12 = b^2 - 4b - 3b + 12 = b(b -4) -3(b - 4) = (b - 3)(b - 4)
Does a plus b plus 2 plus 3 equals 2a plus 3b?
a+b+2+3=5+a+b
3 plus 5 equals 4times b therefore b equals?
3 + 5 = 4*b so 8 = 4*b Divide both sides by 4: 2 = b
Factor b2 plus 4b plus 4?
(b + 2)(b + 2) or (b + 2)2
Factor a squared plus 4a plus 4 - b squared?
(a + 2 - b) (a + 2 + b)
2(a plus b) plus 3(a plus b) plus 5a?
10a + 5b
What is the value of b when 3 times b plus 4 equals b plus 12?
3b+4 = b+12 3b-b = 12-4 2b = 8 b = 4
Calulate in one's digit arithmetic 1 plus 2 plus 3 plus 4 plus 5 plus 6 plus 7?
in ones digit arithmetic to define a+b you take the integer a+b and drop all but the one's digit (same for a x b). 1+2+3+4+5+6+7=8 because you drop all but the one's digit.
A plus b equals 4 and ab equals 2 then a4 plus b4 equals?
1 ------ a+b=4 2 ------ ab=2 ====> 3. b = 2/a Sub 3 into 1 ===> a + 2/a = 4 mutiply both sides by a ===> a2 +2 -4a = 0 use quadratic formula to find a ==> a= 2 +sqrt(2) or a' = 2- sqrt(2) use these two values of a to find a value for b using equation 3 ===> using a, b= 2-sqrt(2) and using a', b= 2+sqrt(2) hence a4 + b4 = (2+sqrt(2))4 + (2-sqrt(2))4 = 136 (for both values of a and b)
What is the answer to 4 divided by b-3 plus 3 divided by b equals -2b divided by b-3?
4/b-3 + 3/b = -2b/b-3 b = 1 or b = -4.5
3a plus 2b - 6 - 2a - b plus 4?
= a + b - 2
