Assuming your equation = 0, then:b3+8b2+7b = 0factor out b:b(b2+8b+7) = 0factor the squared term:b(b+7)(b+1) = 0So the answers are:b = 0b+7 = 0, b=-7b+1 = 0, b=-1
b2 - 7b - 6b = -4(-4)2 - 7(-4) - 6 = 16 +28 - 6 = 38
(a + b)(b + c)
(a+b+c) (a+b-c)
(b + 2)(b + 2) or (b + 2)2
b3 - 5b2 + 12 = (b - 2)(b2 - 3b - 6)Check:(b - 2)(b2 - 3b - 6)= b(b2 - 3b - 6) - 2(b2 - 3b - 6)= b3 - 3b2 - 6b - 2b2 + 6b + 12= b3 - 5b2 + 12
Assuming your equation = 0, then:b3+8b2+7b = 0factor out b:b(b2+8b+7) = 0factor the squared term:b(b+7)(b+1) = 0So the answers are:b = 0b+7 = 0, b=-7b+1 = 0, b=-1
b2 - 7b - 6b = -4(-4)2 - 7(-4) - 6 = 16 +28 - 6 = 38
3 times a times a times b
4(16a4 + b2)
(a + b)(b + c)
It cannot factor without imaginary numbers
(b + 8)(b + 4)
a2 - 4a + 4
(a+b+c) (a+b-c)
a(b+3)+b(b+3)
(a + b)(b - 2c)