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The horizontal velocity has no bearing on the time it takes for the ball to fall to the floor and, ignoring the effects of air resistance, will not change throughout the ball's fall, so you know Vx. The vertical velocity right before impact is easily calculated using the standard formula: d - d0 = V0t + [1/2]at2. For this problem, let's assume the floor represents zero height, so the initial height, d0, is 2. Further, substitute -g for a and assume an initial vertical velocity of zero, which changes our equation to 0 - 2 = 0t - [1/2]gt2. Now, solve for t. That gives you the time it takes for the ball to hit the floor. If you divide the distance traveled by that time, you know the average vertical velocity of the ball. Double that, and you have the final vertical velocity! (Do you know why?) Now do the vector addition of the vertical velocity and the horizontal velocity. Remember, the vertical velocity is negative!
What else can I help you with?
A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant before it hits the ground?
To calculate the velocity of the ball just before it hits the ground, we can use the equation of motion: velocity = acceleration x time. The acceleration due to gravity is approximately 9.8 m/s^2. Given the time of 3.0 seconds, we can plug these values into the equation to find the velocity. Therefore, the velocity of the ball just before it hits the ground is 29.4 m/s.
How long does it take to hit the ground from 28000 feet high?
The answer will depend on what "it" is, and on what its initial velocity is.
Will a ball drop rest reach the ground quicker than the one lunched from the same height but with and initial horizontal velocity?
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
An arrow is shot straight up at an initial velocity of 250ms How long will it take to hit the ground?
This is a velocity question so u need to use uvaxt
If a cricket jumps off the ground with an initial vertical velocity of 4 ft per second afer how many seconds does the cricket land on ground?
To determine how long it takes for the cricket to land back on the ground after jumping with an initial vertical velocity of 4 ft per second, we can use the formula for the time of flight in projectile motion. The time to reach the maximum height is given by ( t = \frac{v}{g} ), where ( v ) is the initial velocity and ( g ) is the acceleration due to gravity (approximately 32 ft/s²). In this case, it takes ( t = \frac{4}{32} = 0.125 ) seconds to reach the peak. Since the time to ascend and descend is equal, the total time until the cricket lands back on the ground is ( 2 \times 0.125 = 0.25 ) seconds.
How long will it take to hit the ground if a baseballl is hit straight up at an initial velocity of 100 ms?
Assuming the acceleration due to gravity is -9.81 m/s^2, the time it takes for the baseball to hit the ground can be calculated using the formula: time = (final velocity - initial velocity) / acceleration. In this case, the final velocity will be 0 m/s when the baseball hits the ground. Calculating it would give you the time it takes for the baseball to hit the ground.
Why velocity is non zero when ball dropped to the ground?
The initial velocity of a dropped ball is zero in the y (up-down) direction. After it is dropped gravity causes an acceleration, which causes the velocity to increase. F = ma, The acceleration due to gravity creates a force on the mass of the ball.
An apple falls from a tree and reaches the ground in 4 seconds with a velocity of 40m/s. What is the acceleration?
Using the acceleration formula, final acceleration is the final velocity minus the initial velocity over elapsed time. Final velocity you gave as 40m/s, and the initial velocity was zero (the apple was stationary on the tree), so the difference is 40 m/s. Divided by the time you gave, 4 s, this will be 10 m/s²
How does initial velocity affect the projectile in range?
The initial velocity of a projectile affects its range by determining how far the projectile will travel horizontally before hitting the ground. A higher initial velocity will result in a longer range because the projectile has more speed to overcome air resistance and travel further. Conversely, a lower initial velocity will result in a shorter range as the projectile doesn't travel as far before hitting the ground.
What do you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
A ball is dropped from a window and takes 2 seconds to reach the ground. It starts from rest and reaches a final speed of 20 MS What is the balls acceleration?
The acceleration of the ball can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the initial velocity is 0 m/s, the final velocity is 20 m/s, and the time is 2 seconds. Therefore, the acceleration would be (20 m/s - 0 m/s) / 2 s = 10 m/s^2.
A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant before it hits the ground?
To calculate the velocity of the ball just before it hits the ground, we can use the equation of motion: velocity = acceleration x time. The acceleration due to gravity is approximately 9.8 m/s^2. Given the time of 3.0 seconds, we can plug these values into the equation to find the velocity. Therefore, the velocity of the ball just before it hits the ground is 29.4 m/s.
A ball is dropped and falls for 3.3 seconds what is the ball's final velocity?
The final velocity of the ball when it hits the ground can be calculated using the equation: final velocity = initial velocity + (acceleration due to gravity * time). Assuming the ball was dropped from rest, the initial velocity would be 0 m/s. With the acceleration due to gravity being approximately 9.8 m/s^2, the final velocity would be 32.34 m/s.
A brick is thrown vertically upward with an initial speed of 2.60 meter per sec from the roof of a building If the building is 100.0 m tall how much time passes before the brick lands on the ground?
Using the kinematic equation ( \text{final velocity}^2 = \text{initial velocity}^2 + 2 \times \text{acceleration} \times \text{distance} ) where final velocity is 0 (at the top) and initial velocity is 2.6 m/s, acceleration due to gravity is -9.8 m/s², and distance is 100 m, you can solve for time to get approximately 5.02 seconds.
How do initial velocity affect range and height of a projectile?
Increasing the initial velocity of a projectile will increase both its range and height. Higher initial velocity means the projectile will travel further before hitting the ground, resulting in greater range. Additionally, the increased speed helps the projectile reach a higher peak height before it begins to descend back down.
What acceleration does a parachutist have when falling before opening the parachute?
A parachutist falling before opening the parachute experiences an acceleration due to gravity of approximately 9.81 m/s^2, which is the acceleration due to free fall. This acceleration causes the parachutist's velocity to increase as they fall towards the ground.
If Chris Bromham took off on his Yamaha and jumped a horizontal distance of 74.0 m across a row of cars and assuming that he started and landed at the same level and was airborne for 1.3 s, what was his initial (angled) velocity as he left the ground?
To find Chris Bromham's initial velocity when he left the ground, you can use the horizontal distance he traveled, the time he was in the air, and the acceleration due to gravity. The equation to use is: horizontal distance = horizontal velocity * time in the air. By rearranging the equation to solve for the horizontal velocity, you can find Chris Bromham's initial velocity when he left the ground.
