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If a ball rolls off the edge of a table two meters above the floor and with an initial velocity of 20 meters per second what is the ball's acceleration and velocity just before it hits the ground?
Wiki User
ā 16y ago
The horizontal velocity has no bearing on the time it takes for the ball to fall to the floor and, ignoring the effects of air resistance, will not change throughout the ball's fall, so you know Vx. The vertical velocity right before impact is easily calculated using the standard formula: d - d0 = V0t + [1/2]at2. For this problem, let's assume the floor represents zero height, so the initial height, d0, is 2. Further, substitute -g for a and assume an initial vertical velocity of zero, which changes our equation to 0 - 2 = 0t - [1/2]gt2. Now, solve for t. That gives you the time it takes for the ball to hit the floor. If you divide the distance traveled by that time, you know the average vertical velocity of the ball. Double that, and you have the final vertical velocity! (Do you know why?) Now do the vector addition of the vertical velocity and the horizontal velocity. Remember, the vertical velocity is negative!
Wiki User
ā 16y ago
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How long does it take to hit the ground from 28000 feet high?
The answer will depend on what "it" is, and on what its initial velocity is.
Will a ball drop rest reach the ground quicker than the one lunched from the same height but with and initial horizontal velocity?
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
An arrow is shot straight up at an initial velocity of 250ms How long will it take to hit the ground?
This is a velocity question so u need to use uvaxt
If the velocity of a particle is nonzero can the particle's acceleration be zero?
yes. If the forces acting on the a moving particle are in equilibrium, (e.g. when a spherical object reaches terminal velocity (neglecting increased air resistance as it gets closer to the ground)) then the particle will be moving at a velocity, that is not 0, yet the velocity will remain constant, and the body will not accelerate or decelerate in any direction, and thus the acceleration is 0.
What speed must an object leave the ground to travel 2.5 meters up?
Using the physics formula: v2 = u2 + 2as v - final velocity u - initial velocity a - acceleration s - distance When the object leaves the ground it is being slowed down by gravity until it stops so the acceleration equals -9.8m/s2 and as it will stop at 2.5 meters v = 0. U is the value we want to find out: 02 = u2 + (2 *-9.8*2.5) 49 = u2 So the object must leave the ground at 7m/s. By the way this is ignoring air resistance.
How long will it take to hit the ground if a baseballl is hit straight up at an initial velocity of 100 ms?
Assuming the acceleration due to gravity is -9.81 m/s^2, the time it takes for the baseball to hit the ground can be calculated using the formula: time = (final velocity - initial velocity) / acceleration. In this case, the final velocity will be 0 m/s when the baseball hits the ground. Calculating it would give you the time it takes for the baseball to hit the ground.
Why velocity is non zero when ball dropped to the ground?
When a ball is dropped, it starts with an initial velocity of zero. However, as it falls towards the ground, it accelerates due to gravity, causing its velocity to increase. Therefore, the velocity of the ball is non-zero as it falls towards the ground.
An apple falls from a tree and reaches the ground in 4 seconds with a velocity of 40m/s. What is the acceleration?
Using the acceleration formula, final acceleration is the final velocity minus the initial velocity over elapsed time. Final velocity you gave as 40m/s, and the initial velocity was zero (the apple was stationary on the tree), so the difference is 40 m/s. Divided by the time you gave, 4 s, this will be 10 m/sĀ²
How does initial velocity affect the projectile in range?
The initial velocity of a projectile affects its range by determining how far the projectile will travel horizontally before hitting the ground. A higher initial velocity will result in a longer range because the projectile has more speed to overcome air resistance and travel further. Conversely, a lower initial velocity will result in a shorter range as the projectile doesn't travel as far before hitting the ground.
What do you need to know to determine how far a projectile travels horizontally?
To determine how far a projectile travels horizontally, you need to know the initial velocity of the projectile, the angle at which it is launched, and the acceleration due to gravity. The horizontal range of the projectile can be calculated using the formula: range = (initial velocity squared * sin(2*launch angle)) / acceleration due to gravity.
A ball is dropped from a window and takes 2 seconds to reach the ground. It starts from rest and reaches a final speed of 20 MS What is the balls acceleration?
The acceleration of the ball can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the initial velocity is 0 m/s, the final velocity is 20 m/s, and the time is 2 seconds. Therefore, the acceleration would be (20 m/s - 0 m/s) / 2 s = 10 m/s^2.
A brick is thrown vertically upward with an initial speed of 2.60 meter per sec from the roof of a building If the building is 100.0 m tall how much time passes before the brick lands on the ground?
Using the kinematic equation ( \text{final velocity}^2 = \text{initial velocity}^2 + 2 \times \text{acceleration} \times \text{distance} ) where final velocity is 0 (at the top) and initial velocity is 2.6 m/s, acceleration due to gravity is -9.8 m/sĀ², and distance is 100 m, you can solve for time to get approximately 5.02 seconds.
A ball is dropped and falls for 3.3 seconds what is the ball's final velocity?
The final velocity of the ball when it hits the ground can be calculated using the equation: final velocity = initial velocity + (acceleration due to gravity * time). Assuming the ball was dropped from rest, the initial velocity would be 0 m/s. With the acceleration due to gravity being approximately 9.8 m/s^2, the final velocity would be 32.34 m/s.
How do initial velocity affect range and height of a projectile?
Increasing the initial velocity of a projectile will increase both its range and height. Higher initial velocity means the projectile will travel further before hitting the ground, resulting in greater range. Additionally, the increased speed helps the projectile reach a higher peak height before it begins to descend back down.
If Chris Bromham took off on his Yamaha and jumped a horizontal distance of 74.0 m across a row of cars and assuming that he started and landed at the same level and was airborne for 1.3 s, what was his initial (angled) velocity as he left the ground?
To find Chris Bromham's initial velocity when he left the ground, you can use the horizontal distance he traveled, the time he was in the air, and the acceleration due to gravity. The equation to use is: horizontal distance = horizontal velocity * time in the air. By rearranging the equation to solve for the horizontal velocity, you can find Chris Bromham's initial velocity when he left the ground.
Will the object that is dropped hit the ground before an object that is that it is thrown horizontally from the same height?
No, both objects will hit the ground at the same time, assuming air resistance is negligible. This is because the time it takes for an object to fall is only influenced by its initial vertical velocity and the acceleration due to gravity, not its horizontal motion.
What acceleration does a parachutist have when falling before opening the parachute?
A parachutist falling before opening the parachute experiences an acceleration due to gravity of approximately 9.81 m/s^2, which is the acceleration due to free fall. This acceleration causes the parachutist's velocity to increase as they fall towards the ground.
