Wiki User
∙ 16y agoThere are a few ways to go about solving this one. Here's one that takes a few steps, but they're easy to follow. What is the average speed of the car during its rapid deceleration? Assuming constant deceleration, it's (80 - 0)/2 = 40 km/s = 11.1 m/s. (I'm playing fast and loose with the signs at this point.) Divide the stopping distance (50 m) by that speed and you get 4.5 seconds. Acceleration, a, is delta V / delta t = -22.2 / 4.5 = -4.9 m/s2. Since the acceleration of gravity is -9.8 m/s2, the deceleration of the car is about half a g. Note that deceleration is the same as negative acceleration.
Wiki User
∙ 16y agoAcceleration = 7.09 ms-2 G's = 7.09/9.8 = 0.72
Acceleration is a change in velocity per unit of time. Velocity is distance (d) per unit of time (t). That makes acceleration distance per unit of time squared, or something like this:We have distance/time2, or d/t2Distance is commonly measured in meters, and time in seconds. This makes acceleration appear in meters per second per second, or meters per second squared, or m/sec2.m/s2meters per second squared
9.8 meters per second squared is the acceleration of gravity.
That's unusual. I guess your teacher is trying to make you think a bit. It's a good mental exercise, though. You may recall that the units of acceleration are meters per second squared. That gives you a clue right there. And if you knew Calculus, you'd know that acceleration is the second derivative of distance, s, with respect to time, t: d2s/dt2. So, by now you're probably getting the feeling that the slope of a distance-time squared graph has something to do with acceleration. And you'd be right. Just as the slope of a velocity-time graph is acceleration, the slope of a distance-t2 graph is acceleration. Well, not quite. It's actually ONE HALF the acceleration.
The sprinter's acceleration is 2 meters per second squared.
Acceleration = 7.09 ms-2 G's = 7.09/9.8 = 0.72
Assuming you want the international units: time: second velocity: meters / second distance: meters acceleration: meters / second2
Acceleration is a change in velocity per unit of time. Velocity is distance (d) per unit of time (t). That makes acceleration distance per unit of time squared, or something like this:We have distance/time2, or d/t2Distance is commonly measured in meters, and time in seconds. This makes acceleration appear in meters per second per second, or meters per second squared, or m/sec2.m/s2meters per second squared
The acceleration of gravity, g, is measured in units of acceleration, which is to say units of distance per time squared. For example, meters per second squared.
Acceleration is typically measured in meters per second squared (m/s^2). This unit represents the change in velocity per unit time.
The acceleration of gravity is approximately 9.81 meters per second squared.
The acceleration of gravity is approximately 9.81 meters per second squared.
The distance traveled can be calculated using the equation: distance = initial velocity * time + 0.5 * acceleration * time^2. If the acceleration is 0.5 m/s^2 and time is 20 seconds, we would need to know the initial velocity to determine the total distance traveled.
g is a measurement of acceleration namely 9.8 meters per second squared. When there is an acceleration of 2g then simply multiply 9.8 meters per second squared times 2 or 19.6 meters per second squared.
The rate at which velocity changes is called acceleration. It can be positive (speeding up) or negative (slowing down), and is given in units of distance per time squared (e.g., meters per second squared).
A distance of 3.2 kilometers = 3,200 meters
A stone that falls from a ledge and takes 8 second to hit the ground travels a distance of 313.6 meters. You can find this answer by substituting 8 seconds for time in the physics formula d = 1/2 x acceleration x (t squared), where d = distance, acceleration is given as a =9.8 meters/second squared, and t squared is time in seconds.