Acceleration = (change in speed) divided by (time for the change) =
(25) / (10) = 2.5 meters per second2
Change of speed divided by time gives you average acceleration. For example, a change of 30 m/s during 5 seconds gives you 6 meters per second square - this is the average acceleration during those 5 seconds. If acceleration is constant, then this is also the acceleration at any moment during those 5 seconds. For more complicated functions (non-constant acceleration), derivates (a topic in calculus) has to be used. Specifically, the acceleration is the derivative of the velocity.
If the acceleration was constant (15 + 25) /2 = 20 (time does not figure into the averaging at all!)
It's a bad question because 5 meters per second per secondis not"a constant speed"it is a rate of acceleration.5 x 5 = 25 meters traveled.
velocity = acceleration x time 27 = acceleration x 10 acceleration = 2.7 m/sec/sec
IF it started out from rest, then V = a t = (7.8 x 30) = 234 meters per secondin the direction of the acceleration, at the end of 30 seconds.
"Constant rate" implies there is no acceleration - acceleration is zero.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
Change of speed divided by time gives you average acceleration. For example, a change of 30 m/s during 5 seconds gives you 6 meters per second square - this is the average acceleration during those 5 seconds. If acceleration is constant, then this is also the acceleration at any moment during those 5 seconds. For more complicated functions (non-constant acceleration), derivates (a topic in calculus) has to be used. Specifically, the acceleration is the derivative of the velocity.
In the first 2 seconds, the velocity of the ball would be given by v = at, where a is the acceleration. Given it traveled 2 meters in 2 seconds, we can use the equation s = (1/2)at^2 to find the acceleration which is 1 m/s^2. So, after 3 seconds, the ball will travel an additional 3 * 1 = 3 meters.
Constant acceleration
If the acceleration was constant (15 + 25) /2 = 20 (time does not figure into the averaging at all!)
It's a bad question because 5 meters per second per secondis not"a constant speed"it is a rate of acceleration.5 x 5 = 25 meters traveled.
Meters/seconds squared
velocity = acceleration x time 27 = acceleration x 10 acceleration = 2.7 m/sec/sec
Seconds are not squared in the acceleration formula. The units for acceleration are meters per second squared (m/s^2), where the time unit (seconds) is squared to represent the change in velocity over time.
The acceleration of the body is 3 m/s²
IF it started out from rest, then V = a t = (7.8 x 30) = 234 meters per secondin the direction of the acceleration, at the end of 30 seconds.