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heres the average 2.2 seconds
900 m/s velocity=meters/sec v=4500/5=900
666.67 seconds
Average Velocity = change in position/change in time V = 35.2 m - 0 m/6.7 s - 0 s 4.8 m/s
a high speed train travels south for 2.00 h for a distance of 454km. what is its average velocity?
heres the average 2.2 seconds
To find the distance traveled in the first 5 seconds, we multiply the average velocity by the time traveled. If the object's velocity is constant, this distance is equal to the velocity multiplied by the time.
3.00 m/s
900 m/s velocity=meters/sec v=4500/5=900
7.5
666.67 seconds
The average velocity can be calculated as the total displacement of the object divided by the total time taken. The object's total displacement during the acceleration phase can be calculated using the equation for uniformly accelerated motion. For the remaining 9 seconds, the object travels at a constant velocity, so the average velocity will be the same as this constant velocity. Calculate the total displacement for the acceleration phase and divide by the total time (15 seconds) to find the average velocity.
Velocity is a vector quantity that includes both speed and direction. To calculate the velocity of Rob on a skateboard, we need to know the distance he traveled in meters and the direction of his motion. If Rob travels 10 meters in 3 seconds, the velocity would be 10 meters/3 seconds = 3.33 m/s (assuming no change in direction).
Average Velocity = change in position/change in time V = 35.2 m - 0 m/6.7 s - 0 s 4.8 m/s
a high speed train travels south for 2.00 h for a distance of 454km. what is its average velocity?
The person travels a total of 4000 m in 400 seconds, so their average speed is 10m/s. However velocity is a vector quantity, and is defined as displacement/time. The total displacement is only 400 m, so the average velocity is just 1m/s.
The distance traveled by the boat can be calculated using the formula Distance = Velocity x Time. Plugging in the values, the distance would be 1.55 m/s x 246 seconds, which equals 380.7 meters.