2 x 10 to power 6 cycles in 1 sec. Period is (1) / (2 x 10 to power 6) = (0.5) x (10 to the power -6) = 0.5 microseconds
1 millisecond = 1,000 microseconds = 1,000,000 nanoseconds 10 milliseconds = 10,000,000 nanoseconds (10 million) = 107
10 o clock
At 10 o'clock the hands of the clock are at an angle of 60°
1 picosecond = 1.0 × 10-6 microseconds1 microsecond = 1 000 000 picoseconds
What is the bit rate of a signal in which 10 bit lasts 20 microseconds?
She Has Her Period In The Middle Of Night At 10 O Clock
She Has Her Period In The Middle Of Night At 10 O Clock
2 x 10 to power 6 cycles in 1 sec. Period is (1) / (2 x 10 to power 6) = (0.5) x (10 to the power -6) = 0.5 microseconds
1.5768 quintillion That is 1.5768 times 10 to the 15th power, or 1,576,800,000,000,000 microseconds
4.32 x 10^10
The period T is the time for one complete cycle of an oscillation of a wave. The frequency f is the number of periods per unit time (per second) and is measured in Hz, or cycles per second. These are related by: f = 1/T Therefore, for a period of T = 20µs = 20*(10^-9)s, f = 1/(20*(10^-9)) f = 20*(10^9) f = 20,000,000,000 Hz = 20 GHz.
Time to send 8*100000 bits = 8000000/1000 = 0.8 microseconds
The definiton of period (T) Is T = 1/f ; Therefore if you know that the period is 2.5 microseconds (=2.5 x 10-6) then the frequency is f=1/(2.5x10-6)= 4 x 105 Hz
Frequency = reciprocal of (' 1 ' divided by) the period = 1 / (27 x 10-6) = 37,037.037 Hz (rounded)
No. There are roughly pi * 10 million seconds in a year, which is around 30 times more than the number of microseconds in a second.
A cesium-133 atom makes 9,192,631,770 cycles per second. Divide it by 4.5 million: 9,192,631,770 / 4,500,000 = 2042.807 Divide 1 second by 2042.807 and the result is 4.895 *10^-4 seconds. If you multiply it by 10^6 you get microseconds: 4.895*10^-4 * 10^6 microseconds/second and that equals 489.5 microseconds.