The period T is the time for one complete cycle of an oscillation of a wave. The frequency f is the number of periods per unit time (per second) and is measured in Hz, or cycles per second. These are related by:
f = 1/T
Therefore, for a period of T = 20µs = 20*(10^-9)s,
f = 1/(20*(10^-9))
f = 20*(10^9)
f = 20,000,000,000 Hz = 20 GHz.
The frequency of a clock's waveform with a period of 35 microseconds can be calculated by taking the reciprocal of the period. Thus, the frequency would be 1 / 35 microseconds, which is approximately 28.57 kHz.
The period of a waveform is the reciprocal of its frequency. For a clock waveform with a frequency of 500 kHz, the period can be calculated as 1 / 500 kHz = 2 microseconds.
The period of a waveform is the reciprocal of its frequency. To find the period (T) in seconds, you can use the formula ( T = \frac{1}{f} ), where ( f ) is the frequency in hertz. For a frequency of 4 MHz (4,000,000 Hz), the period is ( T = \frac{1}{4,000,000} ) seconds, which equals 250 nanoseconds (ns). Therefore, the period of a 4 MHz clock waveform is 250 ns.
It is 100000 Hertz.
A period can't be 4 Hz; those are the wrong units. If the period is 1/(4Hz), then the frequency is 4Hz. If the period is 4 seconds, then the frequency is 0.25 Hz. They are inversely related.
The clock period of a microprocessor is the inverse of its clock frequency. For a clock frequency of 100 MHz, the clock period can be calculated as follows: Clock Period = 1 / Frequency = 1 / 100,000,000 seconds = 10 nanoseconds. Therefore, the clock period is 10 nanoseconds.
At a crystal frequency of 6MHz, the 8085 microprocessor has a clock frequency of 3MHz, or a period of 333 nanoseconds. The NOP instruction requires four clock cycles, three to fetch and one to execute, so the NOP instruction with a crystal frequency of 6MHz would take 1.333 microseconds to fetch and execute. This does not include wait states, each of which would add 0.333 microseconds to the timing.
If the question is what is the waveform for 2 Mhz, then 500nS is the answer (equasion used is f=1/t) If the question is what is the waveform for 2mHz, then 500 S is the answer.
If you have the Maximum clock frequency, then you can figure out the minimum clock period using this formula: 1/(minimum clock period) = (Maximum clock frequency).
The clock period is the time duration of one clock cycle. For a clock frequency of 1 GHz (1 billion hertz), the clock period would be 1 nanosecond (1/1,000,000,000 seconds).
The clock period is calculated as the inverse of the clock frequency. It can be determined using the formula: [ \text{Clock Period} (T) = \frac{1}{\text{Clock Frequency} (f)} ] For example, if the clock frequency is 2 GHz, the clock period would be ( T = \frac{1}{2 \times 10^9} = 0.5 ) nanoseconds.
The clock out frequency of an 8085 is one half the crystal frequency. The period of one T cycle is the inverse of the clock frequency. At a crystal frequency of 5MHz, the clock is 2.5MHz, and T is 400 ns.