The period T is the time for one complete cycle of an oscillation of a wave. The frequency f is the number of periods per unit time (per second) and is measured in Hz, or cycles per second. These are related by:
f = 1/T
Therefore, for a period of T = 20µs = 20*(10^-9)s,
f = 1/(20*(10^-9))
f = 20*(10^9)
f = 20,000,000,000 Hz = 20 GHz.
The frequency of a clock's waveform with a period of 35 microseconds can be calculated by taking the reciprocal of the period. Thus, the frequency would be 1 / 35 microseconds, which is approximately 28.57 kHz.
The period of a waveform is the reciprocal of its frequency. For a clock waveform with a frequency of 500 kHz, the period can be calculated as 1 / 500 kHz = 2 microseconds.
It is 100000 Hertz.
The period of a waveform is the reciprocal of its frequency. In this case, if the frequency is 4 MHz (4 million cycles per second), the period would be 1 divided by 4 million, which equals 0.25 microseconds.
If you have the Maximum clock frequency, then you can figure out the minimum clock period using this formula: 1/(minimum clock period) = (Maximum clock frequency).
At a crystal frequency of 6MHz, the 8085 microprocessor has a clock frequency of 3MHz, or a period of 333 nanoseconds. The NOP instruction requires four clock cycles, three to fetch and one to execute, so the NOP instruction with a crystal frequency of 6MHz would take 1.333 microseconds to fetch and execute. This does not include wait states, each of which would add 0.333 microseconds to the timing.
If the question is what is the waveform for 2 Mhz, then 500nS is the answer (equasion used is f=1/t) If the question is what is the waveform for 2mHz, then 500 S is the answer.
The clock period is the time duration of one clock cycle. For a clock frequency of 1 GHz (1 billion hertz), the clock period would be 1 nanosecond (1/1,000,000,000 seconds).
The clock out frequency of an 8085 is one half the crystal frequency. The period of one T cycle is the inverse of the clock frequency. At a crystal frequency of 5MHz, the clock is 2.5MHz, and T is 400 ns.
A clock with a period of 1 ns has a frequency of 1 GHz, or 1000 MHz.
In the 8085 class machine, machine cycles are measured in microseconds to nanoseconds. For instance, at a clock frequency of 3 MHz, one clock is 333 nanoseconds, and one memory read or write, without wait states, is one microsecond. One CALL instruction, again without wait states, is 6 microseconds.
At a clock frequency of 5 MHz (10 MHz crystal) the 8085 has a clock period of 200 ns. An instruction using 18 cycles would use 3.6 us. (Microseconds)This is for the case with no wait states. Each wait state adds 200 ns. Since an 18 cycle instruction has 5 memory accesses, one wait state per access would add 1 us to the execution time.