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15y ago

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What is the probability of flipping a coin 7 times?

The probability is 1. I have flipped a coin a lot more than 7 times.


A fair coin is flipped three times what is the probability that the coin lands heads each time?

7/8


What is the probability of getting heads at least once if a fair coin is flipped three times?

7/8


If a coin is flipped 20 times and a head comes up 7 times what is the relative frequency of a head coming up?

The relative frequency of an event is calculated by dividing the number of times the event occurs by the total number of trials. In this case, the coin was flipped 20 times, and heads appeared 7 times. Therefore, the relative frequency of getting heads is ( \frac{7}{20} ), which equals 0.35 or 35%.


If a coin is flipped 7 times what is the probability of landing on all tails?

each time you flip the coin, probability to end on either side is 50% (or 0.5) (we disregard landing on the side). So, to land on the same side 7 times, it is: 0.5^7


What is the probibility of getting one head if a coin is flipped three times?

It depends on whether you mean exactly one head or at least one head. There are 8 possible outcomes: TTT, TTH, THH, HHH, HHT, HTT, HTH, THT For at least one head, the probability is 7/8, for exactly one head, the probability is 3/8.


How many possible outcomes are there when you toss a 6 sided die 7 times?

When you toss a 6-sided die 7 times, each toss has 6 possible outcomes. Since the tosses are independent, you can calculate the total number of outcomes by raising the number of outcomes per toss to the power of the number of tosses: (6^7). This equals 279,936 possible outcomes.


If you know that 7 times 8 equals 56how can you use communicative property of multiplication to find the product of 8 times 7?

You could use it because it shows that its just 7 times 8 flipped!


If you toss a coin 10 times and get heads 7 times what is the probability?

7/10


A coin is flipped seven times What is the probability that the outcome is other than all seven heads?

That's the same as the total probability (1) minus the probability of seven heads. So: 1 - (1/2)7 = 127/128


If you toss a coin 8 times there are 256 possible outcomes so how many of these outcomes have exactly 3 heads?

The number is 8!/[3!(8-3)!] where n! = 1*2*3*...*n ie 8*7*6/(3*2*1) = 56


Probability to get exactly 2 heads when flipping a coin 3 times knowing that you get at least one head?

Okay, lets write out the possible outcomes when flipping a coin 3 times: HHH, HHT, HTH, THH, TTH,THT,HTT,TTT That constitures 8 scenarios in which the coin can fall over a 3 flip trial. Now, it is known that you got "at least one head" so therefore we can rule out the no head scenario (TTT) which leaves us with 7. Of those 7 times, how many times does it fall heads exactly twice? Well, we have HHT,HTH,THH. From this you can say that it there are 3 possible outcomes in which you get exactly two heads given that you get at least one head. 3/7.