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Okay, lets write out the possible outcomes when flipping a coin 3 times:

HHH, HHT, HTH, THH, TTH,THT,HTT,TTT

That constitures 8 scenarios in which the coin can fall over a 3 flip trial.

Now, it is known that you got "at least one head" so therefore we can rule out the no head scenario (TTT) which leaves us with 7.

Of those 7 times, how many times does it fall heads exactly twice?

Well, we have HHT,HTH,THH.

From this you can say that it there are 3 possible outcomes in which you get exactly two heads given that you get at least one head. 3/7.

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Q: Probability to get exactly 2 heads when flipping a coin 3 times knowing that you get at least one head?
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