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Q: If a coin is tossed then what is the probability that the number is 5?

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The probability that the die tossed will land on a number that is smaller than 5 is 4/6 or 2/3. Smaller than 5 is 1 - 4 and 6 is the sample space.

First, you find the probability of picking 1 in 5 disregarding order (combination). 5 C 1 = 5/1 = 5 Then you divide that by the possible number of outcomes which is 25. 5/ 2^5= .0195

Each one is 50% Together it's 25% (.5 x .5 = .25)

The probability to get heads once is 1/2 as the coin is fair The probability to get heads twice is 1/2x1/2 The probability to get heads three times is 1/2x1/2x1/2 The probability to get tails once is 1/2 The probability to get tails 5 times is (1/2)5 So the probability to get 3 heads when the coin is tossed 8 times is (1/2)3(1/2)5=(1/2)8 = 1/256 If you read carefully you'll understand that 3 heads and 5 tails has the same probability than any other outcome = 1/256 As the coin is fair, each side has the same probability to appear So the probability to get 3 heads and 5 tails is the same as getting for instance 8 heads or 8 tails or 1 tails and 7 heads, and so on

The chance is 50%-50% that it will be heads or tails; this does not change regardless of the number of previous tosses and their results.

Related questions

1/5 1 out of 5.

It is 5/32 = 0.15625

The probability is 0.5The probability is 0.5The probability is 0.5The probability is 0.5

If a fair coin is tossed 5 times, the probability of getting 5 heads is:P(H,H,H,H,H) = (1/2)5 = 1/32 = 0.03125 = 3.125% â‰ˆ 3.1%

Since a coin has two sides and it was tossed 5 times, there are 32 possible combinations of results. The probability of getting heads three times in 5 tries is 10/32. This is 5/16.

9/2

The probability that both coins are heads is the probability of one coin landing heads multiplied by the probability of the second coin landing heads: (.5) * (.5) = .25 or (1/2) * (1/2) = 1/4

The probability that the die tossed will land on a number that is smaller than 5 is 4/6 or 2/3. Smaller than 5 is 1 - 4 and 6 is the sample space.

These are independent one has no bearing on the other

First, you find the probability of picking 1 in 5 disregarding order (combination). 5 C 1 = 5/1 = 5 Then you divide that by the possible number of outcomes which is 25. 5/ 2^5= .0195

The probability is 90/216 = 5/12

Each one is 50% Together it's 25% (.5 x .5 = .25)

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