Q: Three dice are tossed what is the probability that the same number appears on exactly two of the three dice?

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The probability is 3/8 = 0.375

The probability that the sum is seven all three times is 1/216.

A single fair die has the numbers 1 to 6, so when a single fair die is tossed the probability of obtaining a number different than 11 is: P(x diff than11) = 1.

Since a coin has two sides and it was tossed 5 times, there are 32 possible combinations of results. The probability of getting heads three times in 5 tries is 10/32. This is 5/16.

it is a fair chance so 1/2 :P

Related questions

The probability is 3/8 = 0.375

Coins do not have numbers, there is only the probability of heads or tails.

3/8ths

3 out of 8

The probability that the sum is seven all three times is 1/216.

6/16 = 3/8

The answer depends on how many times the coin is tossed. The probability is zero if the coin is tossed only once! Making some assumptions and rewording your question as "If I toss a fair coin twice, what is the probability it comes up heads both times" then the probability of it being heads on any given toss is 0.5, and the probability of it being heads on both tosses is 0.5 x 0.5 = 0.25. If you toss it three times and want to know what the probability of it being heads exactly twice is, then the calculation is more complicated, but it comes out to 0.375.

The probability that the die tossed will land on a number that is smaller than 5 is 4/6 or 2/3. Smaller than 5 is 1 - 4 and 6 is the sample space.

3/8 * * * * * That is the probability of getting EXACTLY 1H. The prob of getting one (or more) head is 7/8

A single fair die has the numbers 1 to 6, so when a single fair die is tossed the probability of obtaining a number different than 11 is: P(x diff than11) = 1.

Since a coin has two sides and it was tossed 5 times, there are 32 possible combinations of results. The probability of getting heads three times in 5 tries is 10/32. This is 5/16.

The probability is 1/16.