Q: If a drawer contains 10 black socks 12 gray socks and 7 white socks what is the probability the first 2 socks will be black?

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I assume you are selecting two socks (one at a time) from the drawer to wear (for example). There are 6 white + 3 black + 3 brown + 8 gray = 20 socks in all So the probability that the first sock chosen to be white is 6/20 since there are 6 socks and 20 socks in total. 6/20 reduces down to 3/10. The probability that the second sock chosen is also white is 5/19 since there are now only 5 white socks left to be chosen and 19 socks in total (since one sock has been taken out). Thus the probability of both socks being white is: probability = 3/10 x 5/19 = 3/38

There are 52 cards of which 26 (a half) are black. So he probability that the first card is black is 26/52= 1/2

The answer depends on whether or not the first card is replaced before the second is drawn.

A Black Jack is an Ace and a face card (Ten through King). The probability of drawing a Black Jack as the first two cards from a standard deck is 4 in 52 times 16 in 51, which is 0.0241 (Ace First), or 16 in 52 times 4 in 51, which is also 0.0241 (Ace Second).

It is 0.2549, approx.

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Well, if this drawer contains that amount of socks of each color, then you will have a 1:5 probability that the the first sock you draw will be white. 7+4+9=20 4(white)/20(in all) 1(white)/5(all) :D

I assume you are selecting two socks (one at a time) from the drawer to wear (for example). There are 6 white + 3 black + 3 brown + 8 gray = 20 socks in all So the probability that the first sock chosen to be white is 6/20 since there are 6 socks and 20 socks in total. 6/20 reduces down to 3/10. The probability that the second sock chosen is also white is 5/19 since there are now only 5 white socks left to be chosen and 19 socks in total (since one sock has been taken out). Thus the probability of both socks being white is: probability = 3/10 x 5/19 = 3/38

There are 52 cards of which 26 (a half) are black. So he probability that the first card is black is 26/52= 1/2

Bag with 10 marbles: 3 orange, 5 black, 2 white.Rephrasing the question.If a marble is drawn from the bag, then returned to the bag, and a second marbleis drawn, what is the probability that the first marble turns out white and the secondmarble black ?The probability for a marble to come out white from the bag is:P(W) = 2/10 = 1/5The probability for a marble to come out black from the bag is:P(B) = 5/10 = 1/2The probability for a marble to come out white, put back in the bag and then take again a marble for a second time and turns out to be black is:P(B2|W1) = (1/5)âˆ™(1/2) = 1/10 = 0.10 = 10 %

What is the probability that the second tile you pick is yellow? (didnt have enough space to finish the question)

Probability of picking purple sock first time is 6/10 or 3/5, second time, probability is 5/9. Thus 3/5 * 5/9 = 15/45 which cancels to 1/3

The probability that it contains exactly 3 balls is 6/45 = 0.133... recurring.

The answer depends on whether or not the first card is replaced before the second is drawn.

samuel peeps

Use a calculator not the interweb you litttle duck

A Black Jack is an Ace and a face card (Ten through King). The probability of drawing a Black Jack as the first two cards from a standard deck is 4 in 52 times 16 in 51, which is 0.0241 (Ace First), or 16 in 52 times 4 in 51, which is also 0.0241 (Ace Second).

It is 0.2549, approx.