(10/29)(9/28)= 0.110837438 or about 11.1%
There are 52 cards of which 26 (a half) are black. So he probability that the first card is black is 26/52= 1/2
I assume you are selecting two socks (one at a time) from the drawer to wear (for example). There are 6 white + 3 black + 3 brown + 8 gray = 20 socks in all So the probability that the first sock chosen to be white is 6/20 since there are 6 socks and 20 socks in total. 6/20 reduces down to 3/10. The probability that the second sock chosen is also white is 5/19 since there are now only 5 white socks left to be chosen and 19 socks in total (since one sock has been taken out). Thus the probability of both socks being white is: probability = 3/10 x 5/19 = 3/38
The answer depends on whether or not the first card is replaced before the second is drawn.
A Black Jack is an Ace and a face card (Ten through King). The probability of drawing a Black Jack as the first two cards from a standard deck is 4 in 52 times 16 in 51, which is 0.0241 (Ace First), or 16 in 52 times 4 in 51, which is also 0.0241 (Ace Second).
It is 0.2549, approx.
Well, if this drawer contains that amount of socks of each color, then you will have a 1:5 probability that the the first sock you draw will be white. 7+4+9=20 4(white)/20(in all) 1(white)/5(all) :D
To calculate the probability of drawing a black card and a 7 from a standard deck of 52 cards, we first determine the total number of black cards and the number of 7s in the deck. There are 26 black cards (13 spades and 13 clubs) and 4 sevens in the deck. The probability of drawing a black card and a 7 is calculated by multiplying the probability of drawing a black card (26/52) by the probability of drawing a 7 (4/52), resulting in a probability of (26/52) * (4/52) = 1/26 or approximately 0.0385.
There are 52 cards of which 26 (a half) are black. So he probability that the first card is black is 26/52= 1/2
I assume you are selecting two socks (one at a time) from the drawer to wear (for example). There are 6 white + 3 black + 3 brown + 8 gray = 20 socks in all So the probability that the first sock chosen to be white is 6/20 since there are 6 socks and 20 socks in total. 6/20 reduces down to 3/10. The probability that the second sock chosen is also white is 5/19 since there are now only 5 white socks left to be chosen and 19 socks in total (since one sock has been taken out). Thus the probability of both socks being white is: probability = 3/10 x 5/19 = 3/38
What is the probability that the second tile you pick is yellow? (didnt have enough space to finish the question)
The probability that it contains exactly 3 balls is 6/45 = 0.133... recurring.
Bag with 10 marbles: 3 orange, 5 black, 2 white.Rephrasing the question.If a marble is drawn from the bag, then returned to the bag, and a second marbleis drawn, what is the probability that the first marble turns out white and the secondmarble black ?The probability for a marble to come out white from the bag is:P(W) = 2/10 = 1/5The probability for a marble to come out black from the bag is:P(B) = 5/10 = 1/2The probability for a marble to come out white, put back in the bag and then take again a marble for a second time and turns out to be black is:P(B2|W1) = (1/5)∙(1/2) = 1/10 = 0.10 = 10 %
To remove a cabinet drawer, first, open the drawer fully. Look for release tabs or screws on the drawer slides. Press the release tabs or unscrew the screws to detach the drawer from the slides. Lift the drawer up and out to remove it completely.
The answer depends on whether or not the first card is replaced before the second is drawn.
samuel peeps
Probability of picking purple sock first time is 6/10 or 3/5, second time, probability is 5/9. Thus 3/5 * 5/9 = 15/45 which cancels to 1/3
Use a calculator not the interweb you litttle duck