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P(rolls a ten)=3/36=1/12

P(rolls a three)=2/36=1/18

[I am going to assume that if he rolls a ten or three, he also gets his five dollars back, in addition to the winnings.]

Expected value=(1/12)*10+(1/18)*20-(31/36)*5=-85/36, or approximately -2.36

If he doesn't get his five dollars back when he wins,

Expected value=(1/12)*10+(1/18)*20-5=-110/36, or approximately -3.055

[I actually just had this on my statistics final.

I got this one wrong still don't know the answer, but the answer you have isn't one of the possible answers I had.... Maybe -2.78?]

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13y ago

What else can I help you with?