It's equal to positive b squared, or (b x b) .
Of course it is. 'a' can be any positive or negative number, and 'b' is its square.That's no problem.What is difficult is for 'b' to be a negative number in the same equation.No real number for 'a' can produce a negative 'b'.
Take any a, b < 0. Is it true a - b > 0? No. For example: let a = -10000000000000 and b = -1, a - b = -10000000000000 + 1 = -9999999999999 < 0.
By definition (-1)*(-1)=1.(-a)*(-b)(-1)*(a)*(-1)*(b)(-1)*(-1)*(a)*(b)(a)*(b) ■
This depends on what the numbers are. For example,6 + (-4) = 6 - 4 = 2 which is a positive numberOR5 + (-8) = 5 - 8 = -3 which is a negative numberIn general, if you are adding a positive number a to a negative number b,if a is less than b, the result will be negative.if a is greater than b, the result will be positive.
It's equal to positive b squared, or (b x b) .
It can. Negative 2 minus negative 1 = negative 1. However, it sometimes might be positive. Negative 5 minus negative 16 = positive 11. If you have two equal negative variables, such as -a - -a, you will get -2a. -2a may still be positive though, if a is a negative number. An example of having two unequal negative numbers is -a - -b, which is -a + b. That may be positive or negative depending on what a and b are equal to.
Of course it is. 'a' can be any positive or negative number, and 'b' is its square.That's no problem.What is difficult is for 'b' to be a negative number in the same equation.No real number for 'a' can produce a negative 'b'.
10-1 = 1/10 A number raised to a negative power is equal to the reciprocal of the number raised to the power. So a-b = (1/a)b = 1/ab
Take any a, b < 0. Is it true a - b > 0? No. For example: let a = -10000000000000 and b = -1, a - b = -10000000000000 + 1 = -9999999999999 < 0.
a + b = a - bSubtract a from each side:+ b = - bThe only way that 'b' can equal its own negative is if b=0.So (a + b) can equal (a - b) only if b=0.(It doesn't matter what 'a' is.)
By definition (-1)*(-1)=1.(-a)*(-b)(-1)*(a)*(-1)*(b)(-1)*(-1)*(a)*(b)(a)*(b) ■
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There are a lot of long examples that help to visualize why a negative times a negative is a positive, but this is just going to be an algebraic proof. Let x = a*b + (-a)*b + (-a)*(-b) If we factor out the (-a) for the second part of the equation, we are left with: x = a*b + (-a)*(b+(-b)) b+(-b) = 0, so the resulting equation is: x = a*b + (-a)*0 Any number times zero is zero, so: x = a*b Next, we go back to the original equation, and factor our the "b" from the first part, leaving: x = (a+(-a))*b + (-a)*(-b) a+(-a) = 0, so: x = 0*b + (-a)*(-b) 0*b = 0, so: x = (-a)*(-b) Now we see that x equals both a*b and (-a)*(-b), meaning: a*b = (-a)*(-b) So the product of 2 negative numbers must be equal the the product of their positive counterparts, i.e., a positive result.
Taking it step by step: 2b - b - 10 = -13 b - 10 = -13 b = -13 + 10 b = - 3
This depends on what the numbers are. For example,6 + (-4) = 6 - 4 = 2 which is a positive numberOR5 + (-8) = 5 - 8 = -3 which is a negative numberIn general, if you are adding a positive number a to a negative number b,if a is less than b, the result will be negative.if a is greater than b, the result will be positive.
6=5. Which is not a correct problem, but technically is a problem if you look at the definition for "problem"