Wiki User
∙ 14y ago50%
Wiki User
∙ 14y agoMake a punnet square with the mother above, her genotype would be: X^B X^b, and the father to the left whose genotype is X^b Y.The probability of having a colorblind CHILD is 50%. The probability of them having a SON is 50%. Since we are asked what the probability of their SON being colorblind, it is 50% as well. The reason is because the chance of having a colorblind son, among sons only, (according to the punnet square) is 50%.
It depends on a number of different factors. If colorblind is common in either family but the mother/father were lucky enough not to get it, then its a recessive gene. but if its not common in either family then its a very low chance the child will be color blind. Although, if there are numerous people on both sides of the family the probability is very high. It all depends on a lot of different factors. How dominant is the gene? How many relatives are colorblind? If there are any, and they have children, are they colorblind? The easiest way to figure out if the child will be colorblind is to have the kid and test it for colorblind-ness.
I believe the chances of having the same birthday as one of your parents is: 1 out of 183 and the chances of having the same birthday as both parents is: 1 out of 133,225
No
Well quite alot of people have their sons birthdays on similar days (1-2 difference) and I wuould say the chances are about 50/50 but that's just my opinion.:)
Make a punnet square with the mother above, her genotype would be: X^B X^b, and the father to the left whose genotype is X^b Y.The probability of having a colorblind CHILD is 50%. The probability of them having a SON is 50%. Since we are asked what the probability of their SON being colorblind, it is 50% as well. The reason is because the chance of having a colorblind son, among sons only, (according to the punnet square) is 50%.
its impossible
For a couple to have a color-blind daughter, both parents must carry the recessive gene for color blindness. The mother would need to be a carrier with the genotype X^BX^b, and the father would need to have the genotype X^bY. This gives a 25% chance of their daughter inheriting the X^bX^b genotype and being color-blind.
Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind. A woman will carry the colorblindness gene if: a. Her father is colorblind b. Her offpsring are colorblind She may carry the colorblindness gene if: a. Male family members (brothers, uncles, etc.) are colorblind A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy) So, If a woman has normal vision (assuming she does not have a family history of colorblindness), XX, and a man is colorblind, xY, they have several different chances for different offspring: Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) The short answer is that ALL CHILDREN WILL HAVE NORMAL VISION. However, all daughters will be CARRIERS, meaning they can pass colorblindness on to their children.
It depends on a number of different factors. If colorblind is common in either family but the mother/father were lucky enough not to get it, then its a recessive gene. but if its not common in either family then its a very low chance the child will be color blind. Although, if there are numerous people on both sides of the family the probability is very high. It all depends on a lot of different factors. How dominant is the gene? How many relatives are colorblind? If there are any, and they have children, are they colorblind? The easiest way to figure out if the child will be colorblind is to have the kid and test it for colorblind-ness.
Yes, it is possible for a blue-eyed male and a brown-eyed female to have a brown-eyed child. Eye color is a polygenic trait, meaning it is influenced by multiple genes. Both parents can carry genes for brown eyes, and if those genes are passed on to the child, they can have brown eyes even if neither parent has brown eyes.
most likely brown hair
Without having sex? Just by smoking a joint?Very very slim.
no
Your chances of having an ectopic pregnancy from BV is about zero.
If a person does not carry the Sickle cell trait and they marry some one with the trait. The child that comes from that relationship can never have sickle cell disease, however that child has a chance of having the sickle trait.
No, but it increases your chances of having a PLASTIC BABY.