Make a punnet square with the mother above, her genotype would be: X^B X^b, and the father to the left whose genotype is X^b Y.
The probability of having a colorblind CHILD is 50%. The probability of them having a SON is 50%. Since we are asked what the probability of their SON being colorblind, it is 50% as well. The reason is because the chance of having a colorblind son, among sons only, (according to the punnet square) is 50%.
50%Answer100%
100% of all male offspring will be colorblind. 0% of all femal offspring will be colorblind.
It depends on a number of different factors. If colorblind is common in either family but the mother/father were lucky enough not to get it, then its a recessive gene. but if its not common in either family then its a very low chance the child will be color blind. Although, if there are numerous people on both sides of the family the probability is very high. It all depends on a lot of different factors. How dominant is the gene? How many relatives are colorblind? If there are any, and they have children, are they colorblind? The easiest way to figure out if the child will be colorblind is to have the kid and test it for colorblind-ness.
Assuming that the man who has normal vision is homozygous for normal vision, the couple's daughter will either be homozygous for normal vision or heterozygous (normal vision but carrier for color blindness) for normal vision. In light of this, the couple's daughter will not be color blind.
There is no chance for a colorblind daughter because the x-chromosome that comes from the male is normal and then it does not matter which x-chromosome comes from the female because colorblindness is a recessive gene, therefore there is no chance.
If the mother is a carrier of the colorblind gene (XcX) and the father has normal color vision, the probability of their child being colorblind is 50%. This is because the child has a 50% chance of inheriting the Xc chromosome from the mother and developing colorblindness.
50%Answer100%
100% of all male offspring will be colorblind. 0% of all femal offspring will be colorblind.
It all will depend on what kind of (recessive or dominant) alleles are responsible for the colorblind characteristic and what kind of alleles do the parental genes have.
The probability of a colorblind child being born is 50%. This is because the male passes his Y chromosome to all his sons, and since he is colorblind, his sons will inherit the colorblind gene from him. The daughters will inherit their X chromosome from the mother and have a 50% chance of being carriers like her.
It depends on a number of different factors. If colorblind is common in either family but the mother/father were lucky enough not to get it, then its a recessive gene. but if its not common in either family then its a very low chance the child will be color blind. Although, if there are numerous people on both sides of the family the probability is very high. It all depends on a lot of different factors. How dominant is the gene? How many relatives are colorblind? If there are any, and they have children, are they colorblind? The easiest way to figure out if the child will be colorblind is to have the kid and test it for colorblind-ness.
Assuming that the man who has normal vision is homozygous for normal vision, the couple's daughter will either be homozygous for normal vision or heterozygous (normal vision but carrier for color blindness) for normal vision. In light of this, the couple's daughter will not be color blind.
No they will produce a child who is colour blind.
there is a 50% chance that the child will be colorblind. If it is a boy, it will be colorblind, but if it is a girl, it will only be a carrier. Mother's chromosome is XrXr and Father's Chromosome is XRY, which means the children's genotypes will be XRXr if girl and XrY if a boy.
doggies=colorblind
The mother has two defective X chromosomes for color. The father has a normal X (and Y). If they have children and they are girls, the girls will have one defective X and a normal X. That normal X from dad will be enough so she will see color. If a boy, he will have a defective X and a normal Y but will be color blind. Only in the case of one normal X and a defective X would a child have normal vision. The Y chromosome doesn't have any genes for color.
There is no chance for a colorblind daughter because the x-chromosome that comes from the male is normal and then it does not matter which x-chromosome comes from the female because colorblindness is a recessive gene, therefore there is no chance.