This statement is false. A number can be divisible by 3 and still be even, such as the number 6, which is both divisible by 3 and an even number. Divisibility by 3 is determined by the sum of a number's digits, not by whether the number is odd or even. Therefore, being divisible by 3 does not imply that a number must be odd.
If the second number is divisible by 6 then neither first nor second number is odd.
Yes because odd numbers are those which aren't divisible by 2.
If a number is even (divisible by 2) and divisible by 3, then it must also be divisible by 6.
By addition, the sum of an odd number and an even number is always odd. (3 + 2 = 5, 7 + 10000 = 10007 ~ not evenly divisible by 2) By multiplication, an odd number times an even number is always even. (3 x 4 = 12 , 15 x 30 = 450 ~ evenly divisible by 2)
To determine if 154111 is divisible by 6, it must be divisible by both 2 and 3. The number 154111 is odd, so it is not divisible by 2. Since it fails the divisibility test for 2, it cannot be divisible by 6. Thus, 154111 is not divisible by 6.
no 6 is divisible by 3 and so is 24 and so on ! lol
3411 is an odd number and is not divisible by 2. but, it is divisible by 3. 3411/3 = 1137
No. To be divisible by 6, the number must be divisible by both 2 and 3. To be divisible by 2 the number must be even, ie its last digit must be one of {0, 2, 4, 6, 8}; 105's last digit is 5 which is odd so 105 is not divisible by 2. To be divisible by 3, sum the digits of the number and if the result is divisible by 3, then so is the original number. For 1-5: 1 + 0 + 5 = 6 which is divisible by 3 therefore 105 is divisible by 3. Although 105 is divisible by 3 it is not divisible by 2, thus it is not divisible by 6.
5, 7, a bunch of numbers that are odd are not divisible by 3. numbers that are divisible by three can have all their numbers added together and come out with a number that is divisible by 3.
If the second number is divisible by 6 then neither first nor second number is odd.
741 is an odd number so is not divisible by 2 741/3 = 247 so yes divisible by 3
Numbers divisible by 9 have the sum of their digits equal to 9 or a multiple of 9. A number divisible by 2 is an even number. If a 3 digit number is 42n then n can only be 3 if the number is divisible by 9 and 423 is not within the specified range. If a 3 digit number is 43n then n must be 2 for it to be divisible by 9.. The number is thus 432 and this is even and so divisible by 2. If the 3 digit number is 44n then n must be 1 and 441 is odd and not divisible by 2. The only valid solution is 432.
Yes because odd numbers are those which aren't divisible by 2.
NO. Odd numbers are not always divisible by 5. Examples: 3 , 7, 9, 11, 13, 17, ... are odd numbers and they are not divisible by 5.
If a number is even (divisible by 2) and divisible by 3, then it must also be divisible by 6.
An odd number is any integer that is not divisible by 2. To find an odd number that is not a multiple of 5, we can consider odd numbers that are not divisible by 5. One such number is 3, which is odd and not a multiple of 5.
no, as it is an odd number. (3 as the last digit)