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If a rectangle was 5 cm in length and 2cm in width what would be the perimeter?
Wiki User
∙ 14y ago
A rectangle has 2 sides and 2 widths
5 x 2 = 10
2 x 2 = 4
10 + 4 = 14cm
Wiki User
∙ 14y ago
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What measurements do you need to find the area and perimeter of a rectangle how would you use these measurements to find the area and perimeter of a rectangle?
you need length and width length multiply width = area length + length + width + width = perimeter
What is the perimeter of a rectangle if length is 6 and width is 14?
The perimeter would be 40.
How does the length and width of a rectangle relate to the perimeter?
If you add the length and width together, it will always be half of the perimeter. In terms of an equation, it would look like so: Perimeter = (2 x Length) + (2 x Width)
What is the perimeter of a rectangle with length 43 inches?
It is impossible to find the perimeter without the width of the rectangle but if you want a formula it would be (43*2) + 2x. x representing the width
What would the length and width be of an area of 12 and perimeter of 16?
It could be rectangle that has a length of 6 units and a width of 2 units.
What measurements do you need to find the area and perimeter of a rectangle how would you use these measurements to find the area and perimeter of a rectangle?
you need length and width length multiply width = area length + length + width + width = perimeter
What is the width of a rectangle if the perimeter is 75m and the length is 10m?
The width of the rectangle would be 32.5 meters.
What is the perimeter of a rectangle if length is 6 and width is 14?
The perimeter would be 40.
What is the perimeter of a rectangle with length 42 inches?
A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.
How would you find the width if you only know the perimeter and length?
If it's a rectangle, just minus the length from the perimeter twice and than divide what you have by 2. Width = (Perimeter - (length*2))/2
How does the length and width of a rectangle relate to the perimeter?
If you add the length and width together, it will always be half of the perimeter. In terms of an equation, it would look like so: Perimeter = (2 x Length) + (2 x Width)
What is the perimeter of a rectangle with length 43 inches?
It is impossible to find the perimeter without the width of the rectangle but if you want a formula it would be (43*2) + 2x. x representing the width
What would the length and width be of an area of 12 and perimeter of 16?
It could be rectangle that has a length of 6 units and a width of 2 units.
How do you find length of a rectangle with perimeter and width?
you multiply 2 times the width and 2 times the length ad then add them together. the equation would be 2l+2w=perimeter
How do you draw a rectangle with a perimeter of 12 units and an area equalling 8?
The rectangle would have a width of 2 and a length of 4.
What is the perimeter of 7cm by 6cm?
Assuming that this is a rectangle, you know that the length (longer side) would be 7cm, and the width (shorter side) would be 6cm. The formula for perimeter is, 2(length) + 2(width) = Perimeter Now we can plug in our numbers, 2(7cm) + 2(6cm) = 14cm + 12cm = 26cm The perimeter would be 26cm, assuming that this is a rectangle ^^
A rectangle has a width of 12.4 ft and a length of 50 ftwhat is the length of the rectangle?
To answer the question as written: If the length of a rectangle is given as being 50 feet, then the length of the rectangle is 50 feet. To answer the question that is really being asked, if the width of a rectangle is 12.4 feet and the length of 50 feet, the area can be found by multiplying the length by the width. Therefore, the are of the rectangle would be 620 square feet. If however, the question was to determine the perimeter, you would use the formula 2l+2w=p so you would add 12.4 +12.4+50+50, for a perimeter of 124.8 feet.
