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The permiter of a rectangle is 158 in. the length exceeds the width by 43 inches. What is the length and width?
61 inches and 18 inches.
What is the area and perimeter of a shape which is 12.5 x 9?
If that's a rectangle, the area is 112.5 square units and the perimeter is 43 units.
What are the lengths of the sides of 3 rectangles with a perimeter of 12 units only whole numbers?
Perimeter = 2 x (width + length)⇒ 12 = 2 x (width + length)⇒ width + length = 6⇒ the rectangles could be:1 by 52 by 43 by 3[A square is a rectangle with equal sides.]
The perimeter of a rectangle is 126m and the length is 3 more than twice the width Find the dimensions?
Suppose the width is x metres. Then the length is 2x + 3 metres. So the perimeter is 2*[x + (2x+3)] = 2*(3x+3) = 6x + 6 metres ie 6x + 6 = 126 so that 6x = 120 and then x = 20 metres. then 2x+3 = 43 metres. So width = 20 metres and length = 43 metres.
What is the radius of 43 inches?
What is 43 inches? The Area? The circumference? The Diameter? If the diameter is 43 inches than the radius is 21.5 inches If the Circumference is 43 inches than the radius is 6.96 inches If the Area is 43 inches than the radius is 3.7 inches Hope this is helpful :)
