If the "length" of this triangle is the distance from the base to the vertex of the two other sides, it is 100 units^2. (1/2*10*20) if the 'length' is not the aforementioned distance, you do not have enough information.
Length of triangle is 14.4 inches. Check: 0.5*14.4*10 = 72 square inches
Area = Length * width A = 12 * 10 A = 120 units 2
Area = Length * Width = 10*3 = 30 square units.
To find the width of a rectangle, you can use the formula for the area, which is Area = Length × Width. If you know the area and the length, you can rearrange the formula to find the width: Width = Area / Length. For example, if a rectangle has an area of 50 square units and a length of 10 units, the width would be 50 / 10 = 5 units.
length is 30 width is 10
The area of triangle is : 60.0
Length of triangle is 14.4 inches. Check: 0.5*14.4*10 = 72 square inches
60 square feet.
Area = Length * width A = 12 * 10 A = 120 units 2
Area = Length * Width = 10*3 = 30 square units.
To find the width of a rectangle, you can use the formula for the area, which is Area = Length × Width. If you know the area and the length, you can rearrange the formula to find the width: Width = Area / Length. For example, if a rectangle has an area of 50 square units and a length of 10 units, the width would be 50 / 10 = 5 units.
A right triangle has a hypotenuse of length 10 and a leg of length 7 has an area of: 24.99 units2
length is 30 width is 10
length x width= area ex if the length of the square was 10 and the width was 5, 10 x 5= 50units^2
What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in
width 1, length 10 width 2, length 5
area = length x width area = 12 x 10 = 120 square cm