Cb, Db, Eb, Fb, Gb, Ab, Bb, Cb
the midpoint of
ac + cb = ab = 9 2x - 1 + 3x = 9 5x -1 = 9 So 5x = 10 Thereby x =2. Also ac = 3 and cb = 6
A Flat = Ab B Flat = Bb C Flat = Cb D Flat = Db E Flat = Eb F Flat = Fb G Flat = Gb
Gb, Ab, Bb, Cb, Db, Eb, F, Gb
C is the midpoint of Ab . then AC = BC. So AC= CB.
C is not on the line AB.
the midpoint of AB.
C is not on the line AB.
The real answer is Bc . Hate these @
.Ab + c cb + a
.Ab + c cb + a
Cb, Db, Eb, Fb, Gb, Ab, Bb, Cb
Cb, Db, Eb, Fb, Gb, Ab, Bb, Cb
When the ring, R, is an integral domain. That is, when R has no zero divisors. Consider: ab=cb => ab-cb=0 => (a-c)b=0 Then because R has no zero divisors we have: a-c=0 => a=c
the midpoint of
between A and B