the midpoint of
The locus point is the perpendicular bisector of AB. The locus point is the perpendicular bisector of AB.
The Law of Cosines: c^2=a^2 + b^2 -2abcos(ab) , c is the distance between the two points a and b and (ab) is the angle between a and b from the origin. If one point is taken as the origin, and a and b a re taken at right angles to each other, then cos(ab) is zero and you have Pythagora' Theorem..
The answer depends on the information that you have about the four points and the manner in which that information is presented. Suppose the 4 points are A, B, C and D and the point that you find is P. If you have the coordinates of A, B, C and D then gradient AP = gradient AB (or any other pair) will suffice. If you have any one of vectors AB (or AC, AD, BC, BD), then vector AP is parallel to vector AB will suffice.
an example would be if you had line AB who's points are (5,3) and another at (1,5). Connecting diagonally. If you were to put a vertical line anywhere between the points. it only goes through one point. Making it a function.
The real answer is Bc . Hate these @
the midpoint of
If point b is in between points a and c, then ab +bc= ac by the segment addition postulate...dont know if that was what you were looking for... but that is how i percieved that qustion.
between A and B
The locus point is the perpendicular bisector of AB. The locus point is the perpendicular bisector of AB.
The point B lies between points A and C is the distances AB, BC and AC are related by:AB + BC = AC.
C is not on the line AB.
Probably an arc, but it is not possible to be certain because there is no information on where or what point b and c are..
The Law of Cosines: c^2=a^2 + b^2 -2abcos(ab) , c is the distance between the two points a and b and (ab) is the angle between a and b from the origin. If one point is taken as the origin, and a and b a re taken at right angles to each other, then cos(ab) is zero and you have Pythagora' Theorem..
the midpoint of AB.
Zero.For instance, given a right triangle with points ABC. where AC is the hypotenuse, then to find the angle between AB, we take sin(AB/AC), where AB is the distance between points A and B, and AC is the distance between A and C. If we replace AB with 0, the equation would be sin(0/AC). Sine of zero is always zero.
Two distinct points determine exactly one line. That line is the shortest path between the two points. ... Two points also determine a ray, a segment, and a distance, symbolized for points A and B by AB (or BA when B is the endpoint), AB, and AB respectively.