That depends on where the triangle ABC is located on the Cartesian plane for the coordinates of its vertices to be determined.
The answer depends on what ABC is!
I think ABC's
The analytical method is far from simple:Divide the quadrilateral into two triangles, say ABC and BCD.The centroid of triangle ABC is P = [(xa+xb+xc)/3 , (ya+yb+yc)/3] where (xa,ya) are the coordinates of A and so on.Label the centroid of BCD as Q and find its coordinates in a similar way.The next step is to find the areas of the two triangles.Area (ABC) = gArea(BCD) = hThen the centroid of the whole quadrilateral is the weighted average of the coordinates of P and Q, with weights g and h.Thus, if R is the centroid of the quadrilateral, thenxr = (g*xp + h*xq)/(g+h) andyr = (g*yp + h*yq)/(g+h).If you can cut out the quadrilateral the procedure is much simpler. Suspend the quadrilateral from one corner and, using a plumb line or equivalent, mark the vertical direction. Repeat from the adjacent vertex. The two lines will meet at the centroid.
There are 10abc tenths in abc.
Bho
The answer will depend on the original coordinates of A: these have not been provided so neither has an answer.
answer
That depends on where the triangle ABC is located on the Cartesian plane for the coordinates of its vertices to be determined.
2 down 1 up
Find the coordinates of the vertices of triangle a'b'c' after triangle ABC is dilated using the given scale factor then graph triangle ABC and its dilation A (1,1) B(1,3) C(3,1) scale factor 3
It is (10, -2).
(-5, 6)
(9, -5)
(6, -4)
That would depend on its original coordinates and in which direction clockwise or anti clockwise of which information has not been given.
The coordinates of the point P would be definitely 3 6.