To find angle o, we need more context about the relationship between angles 2, p, and o. If angle 2 and angle p are part of a triangle or a straight line, we can use properties of triangles or supplementary angles to find angle o. For example, if angles 2 and p are part of a triangle, angle o would be calculated as 180 - (angle 2 + angle p). Please provide additional information about the angles' arrangement for a specific answer.
obtuse angle
The angle formed is 60 degrees.
The hands of a clock at 2 o'clock will form an acute angle of 60 degrees
To find angle M in triangle MNO, we can use the Law of Cosines. Given side lengths m = 5.6 inches, n = 9.8 inches, and angle O = 95 degrees, we can calculate the length of side o using the formula: ( o^2 = m^2 + n^2 - 2mn \cdot \cos(O) ). Once we have side o, we can apply the Law of Sines to find angle M: ( \frac{m}{\sin(M)} = \frac{o}{\sin(O)} ). After performing these calculations, angle M is approximately 34.2 degrees.
=Strait Angle- An Angle that measures exactly 180* Degrees.=<---------------o--------------->
obtuse angle
The angle formed is 60 degrees.
60o
The hands of a clock at 2 o'clock will form an acute angle of 60 degrees
30 degrees.
150
To find angle M in triangle MNO, we can use the Law of Cosines. Given side lengths m = 5.6 inches, n = 9.8 inches, and angle O = 95 degrees, we can calculate the length of side o using the formula: ( o^2 = m^2 + n^2 - 2mn \cdot \cos(O) ). Once we have side o, we can apply the Law of Sines to find angle M: ( \frac{m}{\sin(M)} = \frac{o}{\sin(O)} ). After performing these calculations, angle M is approximately 34.2 degrees.
Remember the sum of the 3 angles of a triangle = 180degrees Let angle 1 = x angle 2 = 2x angle 3 = x-20 Sum = x + 2x + x - 20 =180o 4x - 20 = 180o 4x = 200o x = 50o 2x = 100 o x - 20 = 30o angle 1 = 50o angle 2 = 100 o angle 3 = 30o
180
=Strait Angle- An Angle that measures exactly 180* Degrees.=<---------------o--------------->
O
The C-O-C bond angle in dimethyl ether (CH3-O-CH3) is approximately 110 degrees. This angle is influenced by the tetrahedral geometry around the carbon atoms and the presence of lone pairs on the oxygen atom, which slightly compress the bond angle. Thus, the C-O-C bond angle is less than the ideal tetrahedral angle of 109.5 degrees due to these factors.