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The numbers are 5, 7, 9, 11 (35 is 64 less than 99) The equation is (A)(A+2) = (A+4)(A+6) - 64 A2 + 2A = A2 +10A +24 -64 2A = 10A - 40 8A = 40 A = 5
a, a + 2, a + 4; a2 + 2a + 22 = a2 + 8a + 16 6a = 6 ie a = 1 and other numbers are 3 & 5.
A1 + A2 = 90 A1 = 4*A2 Substituting from the second equation into the first: 4*A2 + A2 = 90 or 5*A2 = 90 so that A2 = 18 and then, by the second equations, A1 = 4*18 = 72
a1 greater than a2
There are many sets of side lengths that will make a right triangle. Try 3-4-5 or any multiple of those like 6-8-10. Another common one is 5-12-13 or a multiple thereof. The way to check to see if any three side lengths make a right triangle is to use the converse of the Pythagorean Theorem. If the longest side is c, calculate the value of c2 and see if it is less than, greater than or equal to a2 + b2, the sum of the squares of the other two sides. If the quantities are equal, the triangle would be a right triangle. If c2 is less than a2 + b2 the triangle would be acute. If c2 is greater than a2 + b2 the triangle would be obtuse.