The numbers are 5, 7, 9, 11
(35 is 64 less than 99)
The equation is (A)(A+2) = (A+4)(A+6) - 64
A2 + 2A = A2 +10A +24 -64
2A = 10A - 40
8A = 40
A = 5
-1
They are 6, 8, 10 and 12.
The product of two consecutive positive integers can be found by multiplying the smaller integer by the larger integer. If the smaller integer is represented as ( n ), then the larger integer would be ( n + 1 ). Therefore, the product of two consecutive positive integers is ( n \times (n + 1) ).
There are no such integers.
Two negative consecutive odd integers that have a product of 63 are -7 and -9. -7 is larger than -9. -7 is the answer.
-1
They are 6, 8, 10 and 12.
4,6,8,10
The product of two consecutive positive integers can be found by multiplying the smaller integer by the larger integer. If the smaller integer is represented as ( n ), then the larger integer would be ( n + 1 ). Therefore, the product of two consecutive positive integers is ( n \times (n + 1) ).
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
There are no such integers.
Two negative consecutive odd integers that have a product of 63 are -7 and -9. -7 is larger than -9. -7 is the answer.
Divide the sum of the two consecutive odd integers by 2: 156/2=78. The two consecutive odd integers will be one more and one less than 78, so the smaller will be 77 and the larger will be 79.
12 and 13.
The integers are 10 and 11.
The larger integer is 30. The smaller is 28.
x+3 and x+4 would be consecutive integers.