b^(2) = a
Then
b = +/- sqrt(a)
a=b=3.60555
b = 14324.80366
b = sqrt32 or 4 root 2
pythagoras
All the time
a=b=3.60555
4
8^*2) + b^(2) = 18^(2) Algebraically rearranger b^(2) = 18^(2) - 8^(2) Remember two squared terms with a negative (-) between them factors to b^(2) = (18 - 8)( 18 + 8) b^(2) = 10( 26) b^(2) = 260 b = +/- sqrt(260) b = +/- 16.124....
b = 14324.80366
b = sqrt32 or 4 root 2
C equals the square root of 1000 or 31.622776601683793319988935444327...
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
pythagoras
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
(b + 2c)(b - c)
All the time
Pascal