Q: If dealt one card from a standard 52 card deck what is the probability of being dealt an ace or a 9?

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Since there are only four aces in a standard 52 card deck, the probability of being dealt five aces is zero.

If only one card is dealt randomly from a deck of cards, the probability is 1/52.

Probability of 2 of clubs = 1/52 or 0.0192.

The odds of being dealt exactly a full house are 694 to 1 against, which equates to a probability of 0.00144. The probability of all 5 card hands can be found, along with explanations of how to derive the probabilities, can be found at http://www.microcentrics.com/fivecard.aspx.

As there are no 12 cards in a standard pack the probability is zero.

Related questions

The probability is 0. One card cannot be a club and a spade!

If the pack is well shuffled, the probability is 1/52.

Since there are only four aces in a standard 52 card deck, the probability of being dealt five aces is zero.

The probability, if the cards are dealt often enough, is 1.On a single deal, the prob is 3.69379*10^-6

1/26 under the assumption that one is using a standard 52 card deck with no jokers. 1/27 if the jokers are included.

If only one card is dealt randomly from a deck of cards, the probability is 1/52.

The answer will depend on the exact situation.If you are dealt a single card, the probability of that single card not being a queen is 12/13 - assuming you have no knowledge about the other cards.Here is another example. If you already hold three queens in your hand (and no other cards have been dealt), the probability of the next card being dealt being a queen is 1/49, so the probability of NOT getting a queen is 48/49 - higher than in the previous example.

Probability of 2 of clubs = 1/52 or 0.0192.

Counting Aces as a face card, the answer is 0.0241 If Aces are not considered face cards, then the answer is 0.0181

The odds of being dealt exactly a full house are 694 to 1 against, which equates to a probability of 0.00144. The probability of all 5 card hands can be found, along with explanations of how to derive the probabilities, can be found at http://www.microcentrics.com/fivecard.aspx.

As there are no 12 cards in a standard pack the probability is zero.

Probability = Chance of Success / Total Chances (Chance of Success + Chance of Failure) There are 4 aces in a 52 card deck and 48 cards that are not aces. Probability of being dealt an ace = 4 / (4 + 48) = 4/52 = .0769 or about 7.7 percent