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What is the probability of getting dealt two aces in a deck of cards?
The odds are 220:1 of being dealt pocket aces.
What is the combined probability of being dealt a face card and then a three as the second card from a standard 52 card deck?
Counting Aces as a face card, the answer is 0.0241 If Aces are not considered face cards, then the answer is 0.0181
What is the probability you will be dealt 2 aces from a standard 52-card deck?
The probability is 4/52 for the first ace and 3/51 for the second. So the probability of 2 aces is 4/52 x 3/51 = 1/221
You are dealt one card from a 52 deck of cards what is the probability of being an ace?
Probability = Chance of Success / Total Chances (Chance of Success + Chance of Failure) There are 4 aces in a 52 card deck and 48 cards that are not aces. Probability of being dealt an ace = 4 / (4 + 48) = 4/52 = .0769 or about 7.7 percent
What is the probability of getting exactly three aces in a five-card poker hand dealt from an ordinary 52 card deck?
The probability of getting 3 aces in the order AAABB is; P(AAABB) = (4/52)∙(3/51)∙(2/50)∙(48/49)∙(47/48) = 0.0001736... There are 5C3 = 5!/(3!∙(5-3)!) = 10 different ways in which the aces can come out. So the probability of getting exactly three aces in a five card poker hand dealt from a 52 card deck is, P(3A) ~ 10∙(0.0001736) ~ 0.001736 ~ 0.1736%
What is the probability of beind dealt five aces from a standard 52 card deck?
Since there are only four aces in a standard 52 card deck, the probability of being dealt five aces is zero.
What is the probability of getting dealt two aces in a deck of cards?
The odds are 220:1 of being dealt pocket aces.
How often do you get dealt pocket aces in a game of poker?
The probability of being dealt pocket aces in a game of poker is approximately 1 in 221 hands.
What is the combined probability of being dealt a face card and then a three as the second card from a standard 52 card deck?
Counting Aces as a face card, the answer is 0.0241 If Aces are not considered face cards, then the answer is 0.0181
What is the probability you will be dealt 2 aces from a standard 52-card deck?
The probability is 4/52 for the first ace and 3/51 for the second. So the probability of 2 aces is 4/52 x 3/51 = 1/221
You are dealt one card from a 52 deck of cards what is the probability of being an ace?
Probability = Chance of Success / Total Chances (Chance of Success + Chance of Failure) There are 4 aces in a 52 card deck and 48 cards that are not aces. Probability of being dealt an ace = 4 / (4 + 48) = 4/52 = .0769 or about 7.7 percent
If dealt one card from a standard 52 card deck what is the probability of being dealt an ace or a 9?
Aces and 9s are disjoint events, so the probability of either is the sum of the probabilities of each. P(A or 9) = P(A) + P(9) = 1/13 + 1/13 = 2/13
What is the probability of getting 4 aces when dealt with 13 cards?
To find the probability of being dealt exactly 4 aces in a 13-card hand from a standard 52-card deck, we can use the hypergeometric distribution. The total number of ways to choose 4 aces from 4 available is ( \binom{4}{4} = 1 ), and the number of ways to choose the remaining 9 cards from the 48 non-aces is ( \binom{48}{9} ). The total number of ways to choose any 13 cards from 52 is ( \binom{52}{13} ). Thus, the probability is given by ( \frac{1 \times \binom{48}{9}}{\binom{52}{13}} ).
What are the odds of being dealt pocket aces in a game of Texas Hold'em poker?
The odds of being dealt pocket aces in a game of Texas Hold'em poker are approximately 1 in 221, or about 0.45.
What is the probability of being dealt 2 aces in a 5 card poker hand?
If dealt from a randomly shuffled pack it is 0.0399, approx.If dealt from a randomly shuffled pack it is 0.0399, approx.If dealt from a randomly shuffled pack it is 0.0399, approx.If dealt from a randomly shuffled pack it is 0.0399, approx.
What are the odds of being dealt pocket aces in Texas hold 'em?
The odds of being dealt pocket aces in Texas hold 'em is (4 in 52) times (3 in 51) or 12 in 2652 which, reduced, is 1 in 221.
What is the probability of getting exactly three aces in a five-card poker hand dealt from an ordinary 52 card deck?
The probability of getting 3 aces in the order AAABB is; P(AAABB) = (4/52)∙(3/51)∙(2/50)∙(48/49)∙(47/48) = 0.0001736... There are 5C3 = 5!/(3!∙(5-3)!) = 10 different ways in which the aces can come out. So the probability of getting exactly three aces in a five card poker hand dealt from a 52 card deck is, P(3A) ~ 10∙(0.0001736) ~ 0.001736 ~ 0.1736%
