The problem is meaningless without a diagram but I am guessing that ABC make a triangle and D is on the extension of AB beyond B. In that case we use the exterior angle theorem to get CBD = C + A, so 125 = 90 + A and A = 35.
90 degrees
A perpendicular bisector [for a given line segment] is a line that meets it at 90 degrees and divides it into two halves.
No, a segment is not necessarily perpendicular. A segment is simply a straight line connecting two points. A perpendicular segment would be a segment that forms a right angle with another segment or line.
perpendicular bisector
Sure. There's even a special name for that line. It's called the "perpendicular bisector" of the segment.
90 degrees
90 degrees
A perpendicular bisector [for a given line segment] is a line that meets it at 90 degrees and divides it into two halves.
Such a line is called a perpendicular bisector.
Perpendicular Bisector
It bisects the line segment at midpoint at 90 degrees and its slope is the reciprocal of the line segment's slope plus or minus.
It's called a perpendicular bisector of the line segment.
No, a segment is not necessarily perpendicular. A segment is simply a straight line connecting two points. A perpendicular segment would be a segment that forms a right angle with another segment or line.
perpendicular bisector
Yes. it is possible to bisect a segment with a perpendicular segment. Follow the link to learn how to do it: http://www.mathopenref.com/constbisectline.html
no
The perpendicular bisector of a line segment AB is the straight line perpendicular to AB through the midpoint of AB.