The problem is meaningless without a diagram but I am guessing that ABC make a triangle and D is on the extension of AB beyond B. In that case we use the exterior angle theorem to get CBD = C + A, so 125 = 90 + A and A = 35.
90 degrees
A perpendicular bisector [for a given line segment] is a line that meets it at 90 degrees and divides it into two halves.
No, a segment is not necessarily perpendicular. A segment is simply a straight line connecting two points. A perpendicular segment would be a segment that forms a right angle with another segment or line.
perpendicular bisector
The perpendicular line segment construction involves creating a line segment that meets another line at a right angle (90 degrees). This is typically done using a compass and straightedge. First, a point is marked on the line where the perpendicular will intersect. Then, arcs are drawn from this point to establish two points equidistant from it, allowing the straightedge to connect these points, forming a perpendicular line.
90 degrees
90 degrees
A perpendicular bisector [for a given line segment] is a line that meets it at 90 degrees and divides it into two halves.
Such a line is called a perpendicular bisector.
Perpendicular Bisector
It bisects the line segment at midpoint at 90 degrees and its slope is the reciprocal of the line segment's slope plus or minus.
It's called a perpendicular bisector of the line segment.
No, a segment is not necessarily perpendicular. A segment is simply a straight line connecting two points. A perpendicular segment would be a segment that forms a right angle with another segment or line.
perpendicular bisector
no
Yes. it is possible to bisect a segment with a perpendicular segment. Follow the link to learn how to do it: http://www.mathopenref.com/constbisectline.html
The perpendicular line segment construction involves creating a line segment that meets another line at a right angle (90 degrees). This is typically done using a compass and straightedge. First, a point is marked on the line where the perpendicular will intersect. Then, arcs are drawn from this point to establish two points equidistant from it, allowing the straightedge to connect these points, forming a perpendicular line.